I'm not sure what you're asking - is DG distributed generation? Full load would be provided by the DG; if it's a 40MW wind farm, it will be able to provide you with turbine data; each turbine will be able to provide so much kVA. I would use this number (instead of kW output) for sizing of equipment as this would give a maximum. You may also need to take into account any D-VAR and capacitor bank effects on this cumulative KVA.
To calculate the DG set current, you need the load current and the load voltage. To convert it into kilowatts it is divided by 1000.
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.
I=Kva*1000/v*1.732 =500*1000/415*1.732 =500,000/718.78 =695.62 Amps. So max.load of 500kva DG is 695.62 Amps
Full load starting current is typically in the region of 5or 6 times the full load motor current;.
There are several ways to calculate working load limit. One of these includes Minimum Breaking Load (MBL) divided by Working Load Limit (WLL) equals Working Load Limit (WLL).
To calculate the DG set current, you need the load current and the load voltage. To convert it into kilowatts it is divided by 1000.
To calculate the DG set current, you need the load current and the load voltage. To convert it into kilowatts it is divided by 1000.
no load voltage - full load voltage by full load voltage
Rating for DG set and any of electrical machines is calculated in KVA. KVA is calculated as KW/pf. One can calculate the required KVA for DG set with this formulation: (KW/pf)/load rate. For example KW=110, pf=0.8 and one loads the DG at 75%, so KVA= (110/0.8)/0.75=185 KVA.
The oil pressure for the DG sets depends with the load.
The question has to be more specific. Full load amps, watts or voltage. Please restate your question.
To calculate the power factor (pf) of a 1010 kVA diesel generator (DG) set, you can use the formula: [ \text{Power Factor (pf)} = \frac{\text{Real Power (kW)}}{\text{Apparent Power (kVA)}} ] First, determine the real power (kW) output of the DG set, which can be obtained from the manufacturer's specifications or by measuring the actual load. Then, divide the real power by the apparent power (1010 kVA) to find the power factor. Typically, a power factor of 0.8 to 0.9 is common for DG sets.
To calculate the fuse rating level, you typically want to choose a fuse that is slightly higher than the full-load current to avoid nuisance tripping. For a full load of 4 amps, you could choose a fuse rating of 5 or 6 amps.
To calculate the half load speed of an induction motor, you first need to understand that the synchronous speed remains constant regardless of the load. The full load speed is generally slightly less than the synchronous speed due to slip. To estimate the half load speed, you can use the slip at full load and apply it to the synchronous speed, recognizing that slip may change slightly at half load. However, for a rough estimate, you can assume half load speed is close to the full load speed, as the change in speed due to varying loads is minimal in induction motors.
To calculate the alternator regulation with capacitive loading, you first need to determine the no-load voltage (V_no-load) and the full-load voltage (V_full-load) under capacitive conditions. Regulation is then calculated using the formula: ( \text{Regulation} = \frac{V_{no-load} - V_{full-load}}{V_{full-load}} \times 100% ). Ensure to account for the effects of reactive power due to the capacitive load, which can impact the voltage drop and overall performance of the alternator. Additionally, consider the alternator's impedance and the load characteristics for accurate results.
To convert grams (g) to decigrams (dg), you multiply by 10, since 1 gram is equal to 10 decigrams. Therefore, to convert 21.03 g to dg, you would calculate 21.03 g × 10 = 210.3 dg.
The fuel usage will be based on the load applied to the generator and how many KW the generator outputs. The more load the higher the fuel consumption. You do not list the output of the generator nor the load so all I do is point you to the diesel fuel generator consumption chart. Click the link to see the chart where you can figure it yourself.