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How many address lines would be required for an 8K 16 module......12..13..14or15?
Yahoodsl
Here's a brute force approach to figuring this out:
number of address lines ------------- possible addresses
1 ------- 2
2 ------- 4
3 ------- 8
4 ------- 16
....
n ------- (2)^n
So, you need 12 addresses, or 2^12, to provide 4000 byte address locations for a 2 byte wide data bus (the 16 in the name).
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∙ 14y ago
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