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Let N be the number of addresses line

2 megabyte = 2*1024

=2048

N = log (size in bytes) /log 2

N= log 2048/log 2

N=11

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Okon Ufot

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2y ago
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Elizabeth Roberts

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2y ago
good answer, thx
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Bennie Schultz

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2y ago
where did you find that
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Wiki User

14y ago

In order to address 2 megabytes of memory, you need 21 address lines.

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Wiki User

14y ago

It requires 21 address lines to address two megabytes of memory.

221 = 2,097,152

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Wiki User

13y ago

It requires 31 address lines for 2 GB of memory.

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Wiki User

7y ago

You would need at least 22 address lines. If you take 2 to the 22nd power, you get a bit over 4.1 million, and that is the minimum number of addresses you'd need for four megabytes of data.

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Wiki User

12y ago

Two megabytes of memory requires 21 address lines.  221 = 2097152.

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11y ago

21 address lines are required to address two mb of memory. (221 = 2097152)

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13y ago

21

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Q: How many address lines are necessary to address two megabytes of memory?
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Related questions

How many nuMBer of address lines required for 8 MB of memory?

It takes 23 address lines to address 8 mb of memory.


How it requires 21 address lines to address two megabytes of memory?

A computer with N address lines can address 2N different objects in memory. 221 is 2,097,152; in a byte oriented computer, otherwise known as two megabytes.


How many address lines can access a 16MB memory?

for 16 MB memory has 24 address lines


How many no of address lines required in 1MB memory 111622 or 24?

How many no of address lines required in 1MB memory 11,16,22 or 24 u haven't specified correct options! 20 address lines will be required because 1 MB is 1024 KB that is 1024*1024 Byte which is equivalent to (2^10)^2 bytes if ur memory is Byte addressable then address lines required will be 20.


How many nuMBer of address lines required for 1 MB memory?

Firstly we need to convert Mb's into bits i.e 1Mb=1024x1024 = 210x210 =220 That means there are 220 memory locations and we will need 20 address lines.


What is the size of RAM that 8086 can address?

8086 has 20 address lines. Therefore it can address 220 bits or 1,048,576 bits of memory, or roughly 1 MB (mega byte).


How do you calculate number of address lines needeed for 1 MB?

20 address lines are required


How many address lines are requried for 12mb?

There are 24 address lines required for 16 mb. That covers 12 mb. The next step down is 23 address lines, which is 8 mb. The 8085 and 8086/8088 cannot address 12 mb. Only the 80286 and higher can.


How many address lines are required to access 1MB RAM using microprocessor 8086?

The 8086/8088 microprocessor has a 20 bit address bus, so the number of memory locations it can address is 220 or 1,048,576.


How many no of address lines are required for 512 K word memory?

If you are addressing bytes, then 512K words (16 bit words) requires 20 address lines.I gave that answer because the question was categorized 8086/8088. If you are addressing words, then the answer is 19 address lines.


How much memory can be address with 32 bit address bus?

32 bit address bus can access more than 4 gigabytes (232) of memory. Sandeep Kr. Singh (MCA)


How many bits are required to address a 4 megabyte?

The minimum number of address lines required to address 4k of memory is 12.To reach this number, remember that each line has two possibilities and keep doubling as you count off. So one line can be used for two possibilities. Two lines represent four possibilities. Three represent eight. When you get to ten, you have 1024 possibilities. So double to 2048 at 11 and again to 4096 at 12. Or for the shortcut, if you take two to the 12th power, you get 4096.