It depends on what the output voltage is. You only specified the input voltage, not the output voltage. The equation is 75 Kva = {some} amps times {some} kilovolts. (Minus incidental losses, of course, but you still need to know output volts.)
The transformer itself does not pull current. Whatever you connect to the transformer pulls current. Whatever the output voltage of the transformer is, divide that into 600 and you get maximum current possible without burning up the transformer. At 24V that's 25 amps.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
It depends on the rated voltage of its secondary.
The primary current of a transformer depends upon the secondary current which, in turn, depends upon the load supplied by the transformer. There is not enough information in the question to determine the rated primary and secondary currents of the transformer.
Take the KVA and divide it by the voltage. 25/.230 = 109 amps. The transformer can put out up to 50% more that its rated for short durations. So you could get around 150 amps out of a 25 Kva tranformer in a worst case situation.
The transformer itself does not pull current. Whatever you connect to the transformer pulls current. Whatever the output voltage of the transformer is, divide that into 600 and you get maximum current possible without burning up the transformer. At 24V that's 25 amps.
You will need a 3:1 ratio transformer. An output current of 20 amps and a secondary voltage of 47 volts, results in a transformer rated at 940 VA.
There are many ways but never can you multiply the power. <<>> A current transformer is specifically designed, by amp turns, to only output 5 amps. Meters that are connected to CT's have a full range deflection (scale) of 5 amps. To do what you are asking seems pointless as there are no meters with 10 amp full scale deflection.
Different controllers have different outputs depending on how many valves are on each zone. In the device there is a control transformer. Look for the VA output of the transformer's secondary side. Mine states 20 VA at 24 volts. To find the amperage use the following equation. I = W/V. Amps = Watts or VA/Volts. Mine can output 20 divided by 24 = .83 amps. This amperage will be the maximum output in amps that the controller can produce to operate the zone valves. To find the current draw of the primary side of the transformer divide the transformers VA by 120 volts.
Your question is incomplete -- what about the transformer?
This typically has to do with how many amps you can safely pull from the secondary of the transformer.
2.083 amps
For single phase, KVA = (line to ground) * (phase current). A 75kVA 480 to 208Y/120 volt transformer is a fairly common transformer. I assume this is the type of transformer you are referring to. 75k / 120 = 625 Amps. As an FYI, the 208Y voltage is the line to line voltage, which is equal to (phase 1) - (phase 2), where the phases are separated by 120 degrees, thus (phase 1) * 1.732 For three phase, kVA = (line to line voltage) * (phase current) *(sqrt 3), 75k / 208 / 1.732 = 208 Amps.
To answer this question a voltage must be given.
There is not enough information provided to answer. KVA is short for "Kilo Volt Amperes". That is, thousands of Volt Amps. In order to determine how many Amperes are flowing, you must know at what voltage it is operating. Amperes = 45,000 ÷ volts Bill Slugg
It depends on how many amps it was designed for. A 12.5kV/600v 10kVA 3 phase transformer can handle ~.5 amps on the primary and ~10A on the secondary. A 600/120V 10kVA 3 phase transformer can handle ~10A on the primary and ~50 on the secondary.
It depends on the rated voltage of its secondary.