A: Actually it is only one transistor required for amplification the other junction can be a diode. As current Begin to flow it causes a bias across one junction which is opposite biasing for the other, A good differential amplifier will have those junction virtually at the same point with a very good current source because any mismatched will cause and output without any input. It is called voltage offset on the other end if the feedback current is very small it will also produce an output voltage offset known as current offset or basically errors
Transistor will be in OFF mode.
Yes1
Collector-to-Emitter resistance is high when the transistor is biased off.
a transistor in active region when emitter junction is forward biased nd collector junction is reverse biased
To know if a transistor is PNP or an NPN,the following should be verified:For a PNP transistor, the base-collector junction is forward biased while the base-emitter junction is reversed biased.For an NPN transistor, the base-emitter junction is forward biased while the base -collector junction is reversed biased.
Emitter-Base junction should be forward biased.Collector-Base junction should be reverse biased.
Transistor will be in OFF mode.
Transistor will be in OFF mode.
Yes1
Voltage is applied between the collector and emitter. A signal is applied between the base and emitter. The input signal will control how much the transistor turns on and the larger current flowing across the Collector/Emitter will be the same, but larger, than the input. Therefore amplified.To keep the transistor switched on and to prevent the input signal switching it off, the transistor has to be biased on. This is usually done with a network of resistors on the base, raising the voltage to keep it conducting.
When both junctions of an NPN transistor are reverse biased, the transistor is in the cutoff mode. In this mode, the transistor is effectively turned off, and it does not conduct current between the collector and emitter. As a result, the transistor behaves like an open switch, preventing current flow in the circuit.
In the context of a bipolar junction transistor (BJT), the saturation region refers to the state where both the base-emitter and base-collector junctions are forward-biased, allowing maximum current to flow from collector to emitter. The active region occurs when the base-emitter junction is forward-biased while the base-collector junction is reverse-biased, enabling the transistor to amplify signals. The cutoff region is when both junctions are reverse-biased, resulting in minimal current flow, effectively turning the transistor off. These regions define the operational modes of the transistor in electronic circuits.
A transistor acts like a valve or gate that opens and closes, and allows a current to flow. Since the amount of current that flows is controlled by another input, they can be used to make amplifiers. Carbon microphones and vacuum tubes have the same property, and so have also been used to make amplifiers historically.
All of the transistors must be biased in their operating range to work correctly.
Transistor works as amplifier,oscillators,switch only when it is biased properly.biasing can be defined as how much amount of voltage that has to be supplied to each junction of the transistor in order to make it work as any one of the above given types.biasing voltage can be decided by seeing the V to I graph of a transistor
A: Actually it is only one transistor required for amplification the other junction can be a diode. As current Begin to flow it causes a bias across one junction which is opposite biasing for the other, A good differential amplifier will have those junction virtually at the same point with a very good current source because any mismatched will cause and output without any input. It is called voltage offset on the other end if the feedback current is very small it will also produce an output voltage offset known as current offset or basically errors
Collector-to-Emitter resistance is high when the transistor is biased off.