4 volt
It's the voltage required for something to work. Cars usually have 12 volt electrical systems, so every electric consumer in a car, lights, radio etc needs a 12 V input voltage.
The circuit is incomplete, you will have no continuity, no flow of current to the load or other components. The voltage across every component in the circuit is zero. No part of the circuit stores or dissipates any energy. In short, the circuit doesn't work.
it is cheaper to use high voltage of transmission because, it is cheaper to boost the voltage up really high and keeps the current low, also the big pylons with huge insulators will reduce the energy wasted. the transformer have to step the voltage up for efficient transmissions and it bring back down to safe usable levels. the voltage is increase by a step up transformer it's then reduced again at the consumer end using a step down transformer. The only thing missing from the above narrative is the reason itself: Every conductor has some resistance. When an electric current flows through a conductor, the resistance of the conductor causes loss of some of the energy. The loss is LESS when the voltage is higher and the current is smaller. The big pylons, the huge insulators, and all the step-up and step-down transformers wouldn't be necessary if the voltage was the same 110 volts all the way from the generating plant to your house. But shipping it at high voltage saves more energy than the cost of all that extra infrastructure.
Every component in a series circuit must have a potential difference across its terminals if current is to flow through that component. We call each of these individual potential differences a 'voltage drop', which is actually a bit of a misnomer as it's not really a 'drop' at all; it would be better termed a 'distribution'. The sum of these 'voltage drops' will then equal the supply voltage applied to the entire circuit.
Kirchoff's voltage law and Kirchoff's current law
Voltage has the dimensions of energy / charge, in SI units, J/C. Depending on what you mean by "energy ... available", you can simply divide the energy by the charge. If there is a certain number of volts between two points - for example 10 volts - that means that every coulomb of charge gains 10 joules of energy in one direction, or loses 10 joules of energy in the other direction.
calulate the voltage of a battery that provides 20 joules of energy to every 5 coulombs of charge
Each Coulomb of charge passing through a 6V battery gains 6 Joules of energy. This can be calculated using the formula Energy = Charge x Voltage. So, for every Coulomb of charge passing through a 6V battery, it receives 6 Joules of energy.
That depends on the voltage. In general, a coulomb of charge will either gain or lose (depending on the direction) one joule of energy for every volt of potential difference. For example, if the battery has 12 V, a coulomb of charge will gain or lose 12 joules of energy when going from one terminal to the other.
If all the bulbs are connected in parallel, and there is enough current, yes, the brightness will be the same. The voltage (which is the amount of energy in every charge), remains the same for all bulbs
you have renewable energy because when you sleep, your energy charges. If it didn't charge, you won't be able to move every day.
A capacitor needs current to flow into and out of it before a voltage is developed across it, so in an ac circuit the current in a capacitor is 90 degrees or a quarter-cycle in front of the voltage. In a 50 Hz system the cycle period is 20 milliseconds so the current peak is 5 milliseconds before the voltage peak every time. The energy in the capacitor is the charge times the voltage, and energy flows into the capacitor and back into the supply twice per cycle. No net energy is dissipated in the capacitor. All the energy is reactive, in other words it flows in and out. The power-factor of the capacitor seen as a load is zero.
No. Energy packs are available every 24 hours
The transformer doesn't "boost" energy. If the voltage on the output side is higher than the voltage on the input side, then the current is lower. The power (energy every second) on either side is the product of (voltage) times (current), and that product is the same on both sides of the transformer.
They describe completely different things.* Voltage: The energy required to move a unit charge between two points * Current: Roughly speaking, the amount of electrons that pass every second * Frequency: The number of cycles per second (for an alternating current) * Conductance: How easily a material will conduct electricity * Power: The amount of energy converted per second
As energy flows through each ascending level of a pyramid of energy, some energy is lost as heat due to metabolic processes like respiration and movement. This results in a decrease in available energy at each higher trophic level. Thus, the amount of energy available to organisms at higher trophic levels becomes progressively smaller.
<p><p> Voltage = 6 V Charge = 1 C Current * Time = Charge V * t = Q Energy = Current * Voltage * Time E = VIt E = Q * V E = 1 C * 6 V E = 6 Joules Therefore energy given to each coulomb of chare passing through 6 V battery is 6 Joules . Cheers !