0
What else can I help you with?
How does load current varies with the load resistance?
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
What are the relationships between current power and resistance?
Power is inversely proportional to resistance. Ohm's law: Current is voltage divided by resistance Power law: Power is voltage times current, therefore power is voltage squared divided by resistance.
How are volts ohms and watts affected by each other?
For a fixed resistance (ohms) current increases as voltage increases. Since Watts equals Volts x Amps x Power Factor then Watts would increase as voltage increases. The resistance would usually be fixed, but if you had a variable load resistance as the resistance decreased and the voltage remained constant, the current would increase and watts would therefore increase. Watts = Volts x Amps x Power Factor Volts = Amps x Ohms Power Factor is 1 for a resistive load.
What is the 3 phase generator capacity in KVA of load current of 17.1 amperes?
voltage=400 volts current=17.1 ampere assumed total load since IL=KVA X 1000x0.8/400 therefore kva=17.1x400/1000x08 =8.55kva Gen set
If you doubled the load resistor in a wheatstone bridge. the load current would not be half as much Why not?
Because by increasing the load resistance, the total circuit resistance is reduced. This means with less resistance, there is more current drawn from the source. Doubling the size of a load resistor increases the load current.
What is the voltage across a load given that the current though it equals 30mA and resistance of the load is 1000 ohms?
Ohm's law: voltage is current times resistance 0.03 amperes times 1000 ohms = 30 volts.
What is the current drawn when you have a single phased load of 200KW is supplied at 500v through an overhead line with a resistance of 0.1ohm per conductor?
If the voltage is 500 volts, and the power is 200 kilo-watts, then the current is 400 amperes. (Watts equals Volts time Amperes)The resistance of the conductor has nothing to do with this calculation, but that fact that the conductors are 0.1 ohms means that the voltage drop across each conductor is 40 volts. (Volts equals Amperes times Ohms) Since there are two conductors, the total voltage drop is 80 volts, and the voltage available to the load will be 420 volts.
If the potential difference across a load is 60 volts and the resistance of the load is 10 ohms the current is amperes.?
It's not that simple. The basic formula is Volts / Ohms = Amps. For 30 Volts you'd get 0.5 Amps, for 60 Volts you'd get 1 Amp, for 120 Volts you'd get 2 Amps.
What will be the load voltage if load resistance is 10 k ohm and load current is 2 ma?
The load voltage can be calculated using Ohm's Law: V = I * R, where V is the voltage, I is the current, and R is the resistance. Substituting the values, V = 2 mA * 10 k ohm = 20 V. Therefore, the load voltage will be 20 volts.
What size resistor needed to drop 3 volts dc to 2.5 volts dc?
You will need to take the resistance of the load into account if you are going to design a voltage divider. The resistance of the load can completely change the voltage ratio of a voltage divider if not factored into the calculation. you can measure or read R(load), then R(needed) = 0.8 R(load)
How any volts are produced in a circuit with 40 amp's of current flowing through a wire with 5 ohms of resistance?
It is a voltage (potential) applied to a load that causes a current to flow through the load. Ohm's Law encapsulates this principal and states Volts = Current x Resistance. In your example, the applied voltage would be 200 volts.
How does load current varies with the load resistance?
Load current is related to load resistance by an inverse relationship. The load current increases linearly as load resistance decreases. Remember, the less resistance, the more current.
How do you work out amps in an electrical circuit?
Current symbol I =voltage/resesistance I=V/R for direct current (dc) and for a resistive load in alternating current (ac)
Determine the secondary and primary current for a transformer which has primary voltage 1440V and secondary 240V and turns ratio of 6 if the secondary is loaded with a resistive load of 60 ohms?
An ideal lossless transformer with a primary voltage of 1440 and a secondary voltage of 240 will deliver 4 amperes to a 60 ohm load by ohms law 240 volts divided by 60 ohms causes 4 amperes to flow through the 60 ohm load. The power delivered to the 60 ohm load will be 4 amperes times the 240 volts or 960 watts. The current in the primary is divided by the primary to secondary ratio of 6. Thus, the primary current will be 4 amperes divided by 6 or 2/3 ampere. The power going into the primary will be 1440 volts times 2/3 amperes or 960 watts. In a real transformer there is losses that make the numbers change. The output voltage will be slightly less and the resistance and reactance of the windings lower the output.
Why the electrical power in house is measured in volts like 230 volts but not like 230 amperes?
Because 230-V supply voltage is fixed, whereas the current depends on the connected load and can vary tremendously.
If you multiply amps times volts the answer will be in units of?
Voltage, measured in volts. <><><> This question is derived from the fundamental relationship between electrical components which is known as Ohms Law: V = I x R where V = voltage (Volts), I = current (Amps) and R= resistance (Ohms).
What value of diode if the load current is 12 amperes?
A: It can be assumed to be .7 to .8 volts if it can carry that current of 12 amps. A diode in the forward direction follows an exponential curve after it reaches . 6 volts across any farther current increase will effect this drop only slightly
