voltage=400 volts current=17.1 ampere assumed total load since IL=KVA X 1000x0.8/400 therefore kva=17.1x400/1000x08 =8.55kva Gen set
One horsepower electric is defined as 746 watts, so 300 horsepower is 224 KW. You don't say what the power factor is, so lets assume 0.85. Divide 224 KW by 0.85, and you get 263 KVA. You are running three phase, no doubt, so divide by 3 to get 88 KVA per winding. Lets assume 480 three phase delta, so divide by 480 to get 183 amperes per winding. Finally, look at motor efficiency. Lets assume 0.95, giving 192 amperes per winding. To translate between winding current and phase current in balanced three phase delta, multiply by the square root of 3, giving a phase current of 333 amperes per phase. That's a lot of current, requiring very large windings and conductors, and it would be a very large motor. I would use a motor with a higher voltage, perhaps 4160. This would bring the current down to around 22 amperes per winding, or 38 amperes per phase, a more reasonable value for such a large motor.
Yes, but only for balanced loads (current in all three phases the same value). The voltage value used is the phase to phase voltage.
A simple Rotary phase converter is just a motor generator set. An electric motor running on the input voltage/current/phase/frequency. it drives a generator that supplies a different voltage/current/phase/frequency. So an electric motor and an electric generator connected together mechanically, either on the same shaft, or via gears, constitutes a Rotary phase converter. the above is incorrect, the motor/generator is the same motor, just one 3 phase motor is needed, it will run on T1 and T2, and put out L1, L2, and L3. You just need to know how to wire it up and what to do to get it to spin over on simple single phase 220, it will create three phase 220.
Divide 2.2 kW by (an assumed, because you did not state it) power factor of 0.85 to get 2.6 kVA. Divide that by 3 to get 0.863 KVA per winding. Divide that by 415 volts to get 2.08 amperes per winding. If you are running star, then that is the phase current. If you are running delta, then multiply by the square root of 3 (1.732) to get 3.6 amperes per phase.
- For a single phase supply @ 220 voltscurrent drawn by 5kva UPS = 22.7 amperes (at full load.)
304 Amperes
to calculate the motor full load current one should know motor power factor, supply voltage and phase of supply. Assuming your motor is with 0.85 pf and 3 phase, 415V source then P = (Sqrt3)*V*I*pf 18500 = 1.732*415*0.85*I hence I = 30.2A
the current carrying capacity of 16sq.mm copper conductor is as below: For Single phase A.C or D.C is - 76 amperes (VIR insulated) and that For Three phase A.C or D.C is - 66 amperes. (rubber insulated)
any more load will add to that phase ,over current protection will trip the generator.
There is no such thing as a 'total current' for a three-phase generator in the sense that you suggest -i.e. the sum of the phase currents. Current ratings are based the current that the machine can deliver to a load on a 'per line' basis.
15kw
Yes, except that the correct term is 'line' conductor, not a 'phase' conductor.
You can't. Measure the amperes simply tells you what the current is.
It's an electrical generator converting mechanical power into electrical power. The electrical power comes out in the form of single-phase alternating current.
differential protection
To answer this question a voltage must be given to find the current output. Also whether the generator is three phase or single phase.
For a single-phase transformer, divide the ratedapparent power (expressed in volt amperes) by the voltage rating (expressed in volts) of the primary winding; this will give you the rated primary current (expressed in amperes) of the primary winding.