no internal resistance of a cell cannot be considered to b as a defect because the resistance is so small as compared to the output we get from a cell this ristance can be neglected..
pata nahi
The internal resistance of a device is the resistance in ohms of that device. It is the resistance electrons need to overcome before electricity is said to flow.
internal resistance is always infinite in ideal current source .the internal resistance is in shunt with current source
its a liquid
zero
Resistivity effects internal resistance of a cell experiment by not allowing the cell to react. Internal resistance experiments are performed in advancing physics classes.
You can measure the emf of a cell by using a voltmeter, as this draws current from a cell. You can use the voltage, the emf, and the load resistance to determine the internal resistance of the cell.
The internal resistance of a cell is not constant because a cell needs to move and be flexible in order to undergo various osmosis or diffusion processes.
it's "ohm".
pata nahi
due to the electrolyte present between the two electodes of the cell
The internal resistance of a dry cell can increase over time due to chemical reactions taking place within the cell that can degrade the electrodes and electrolyte. This can lead to the build-up of resistance within the cell, affecting its overall performance and reducing its ability to deliver current effectively. Additionally, factors such as cell aging and discharge cycles can contribute to the increase in internal resistance over time.
Well, you do use a multimeter to measure it, but not directly. You need at least one other thing besides the multimeter and the dry cell. Here's a simple way to do it: -- Take a resistor. With the meter set to measure resistance, measure the resistor's value. Call that 'R'. -- With the meter set to measure voltage, measure the voltage of the dry cell. Call it 'V1'. -- Connect the resistor across the dry cell. Measure the dry cell's voltage again. Call it 'V2 ' this time . V2 will be less than V1 . The internal resistance of the dry cell is R times (V1 - V2) / V2
It causes the battery's voltage to drop when a current is drawn from it.
A cell has internal resistance, which means that some of the potential(voltage) it provides is used up just in getting current out of the cell and into the circuit.
I don't think you can do that, with the information provided.
It depends on the application. Voltmeters have a high internal resistance, while ammeters have a low internal resistance.