due to the electrolyte present between the two electodes of the cell
The internal resistance of a cell is not constant because a cell needs to move and be flexible in order to undergo various osmosis or diffusion processes.
Well, you do use a multimeter to measure it, but not directly. You need at least one other thing besides the multimeter and the dry cell. Here's a simple way to do it: -- Take a resistor. With the meter set to measure resistance, measure the resistor's value. Call that 'R'. -- With the meter set to measure voltage, measure the voltage of the dry cell. Call it 'V1'. -- Connect the resistor across the dry cell. Measure the dry cell's voltage again. Call it 'V2 ' this time . V2 will be less than V1 . The internal resistance of the dry cell is R times (V1 - V2) / V2
I don't think you can do that, with the information provided.
The EMF of a cell is the voltage across the terminals at zero current. This is the quoted cell voltage but as soon as a current is dawn from the cell, the voltage will drop. It's due to the internal resistance of the cell. In a circuit diagram, a cell is often shown as a voltage source (a perfect source) and a resistor in series to represent the internal resistance. Using Ohms Law, it can be seen that as soon as a current flows, a voltage will be developed across the internal resistance, so reducing the voltage that is seen at the terminals of the cell. The higher the current draw, the higher the voltage drop inside the cell. Normally, the voltage drop is minimal but in most cells, as it loses charge, the internal resistance rises. Eventually it will reach the point where most of the voltage is dropped across the internal resistance, leaving little to drive the intended load. Often, if a battery is removed from a device and measured, the voltage will be measured as equal to or very close to the quoted cell voltage. It is easy to make a judgment that a battery is good when it is almost dead. The only way to confirm the state of the battery is to measure the voltage at the terminals while the load is attached. The results can be very different to the off load voltage. Alkaline cells have a low internal resistance compared to other dry cells. This makes them well suited for high current drain applications. The internal resistance also rises more slowly than most other cells, so they remain useful far longer than zinc-carbon types.
No, it is desirable for a battery to have a low internal resistance.
Resistivity effects internal resistance of a cell experiment by not allowing the cell to react. Internal resistance experiments are performed in advancing physics classes.
You can measure the emf of a cell by using a voltmeter, as this draws current from a cell. You can use the voltage, the emf, and the load resistance to determine the internal resistance of the cell.
no internal resistance of a cell cannot be considered to b as a defect because the resistance is so small as compared to the output we get from a cell this ristance can be neglected..
The internal resistance of a cell is not constant because a cell needs to move and be flexible in order to undergo various osmosis or diffusion processes.
pata nahi
it's "ohm".
The internal resistance of a dry cell can increase over time due to chemical reactions taking place within the cell that can degrade the electrodes and electrolyte. This can lead to the build-up of resistance within the cell, affecting its overall performance and reducing its ability to deliver current effectively. Additionally, factors such as cell aging and discharge cycles can contribute to the increase in internal resistance over time.
Well, you do use a multimeter to measure it, but not directly. You need at least one other thing besides the multimeter and the dry cell. Here's a simple way to do it: -- Take a resistor. With the meter set to measure resistance, measure the resistor's value. Call that 'R'. -- With the meter set to measure voltage, measure the voltage of the dry cell. Call it 'V1'. -- Connect the resistor across the dry cell. Measure the dry cell's voltage again. Call it 'V2 ' this time . V2 will be less than V1 . The internal resistance of the dry cell is R times (V1 - V2) / V2
It causes the battery's voltage to drop when a current is drawn from it.
A cell has internal resistance, which means that some of the potential(voltage) it provides is used up just in getting current out of the cell and into the circuit.
I don't think you can do that, with the information provided.
It depends on the application. Voltmeters have a high internal resistance, while ammeters have a low internal resistance.