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Yes it is. The filament in a standard incandescent bulb is a type of resistor. An incandescent light bulb contains tungsten which reduces electricity and converts electricity to heat and light. All incandescent bulbs are resistors, but only a fraction of resistors are bulbs.
If you want to see if a bulb is a resistor, try adding another bulb in series without changing the voltage. Both bulbs will be very dim. Another way to test this is to get a multimeter and set the meter to the resistance setting. If you get any value other than zero, then it is functioning as a resistor.
Wiki User
∙ 6y ago
Wiki User
∙ 13y agoA: NO it has resistance and act like a resistor but it is not linear like a resistor. So the part should be dignify with the proper name to tell all that that is not a resistor but a bulb.
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What does the resistance in an electrical circuit limit?
Current flow. It's also worthy of noting that a resistor doesn't limit-by, it limits-to, and the current is dependent on the voltage. I[A] = U[V] / R[ohm] It's also worth to note, that the power flowing through said resistor with resistance R is I[A] * U[V] for DC circuits - helps to remember this well when picking appropriately-rated resistors for replacement. Example: let's say we have a 20-ohm, 2W resistor. If we place it in a circuit with 5V, we will get 5V / 20ohm = 250mA (0.25A) of current flowing through the resistor. The power the resistor will "see" is 250mA * 5V = 1.25W, so it's safe. But let's now put that same resistor in a 12V circuit. The current flowing will be 12V / 20ohm = 600mA (0.6A), and the power will be 600mA * 12V = 7.2W, so the resistor will burn.
What is the voltage drop through a resistor of 6 ohms and 2 amps?
12 volts...! The voltage drop across a 2 ohm resistor depends on the current flowing through it. As voltage (E) equals current (I) times resistance (R), if 1/2 amp is flowing through your 2 ohm resistor, 1/2 times 2 = 1 volt. If 1 amp is flowing through your 2 ohm resistor, 1 times 2 = 2 amps. Piece of cake. If the two ohm resistor is the only component in the circuit, it will drop whatever the applied voltage is. Put a 2 ohm resistor across a 6 volt battery, it drops 6 volts. If you put your 2 ohm resistor across a 9 volt battery, it drops 9 volts. Another way to say voltage drop may help. The voltage drop across a resistor is the voltage it "feels" when in a circuit. And that last couple of examples says that very well. In a circuit where a given resistor is the only component, it drops all the voltage in the circuit. It "feels" all the voltage in the circuit. In a circuit where there are 2 resistors of equal value in series, each one drops or "feels" half of the applied voltage. (The sum of the voltage drops equals the applied voltage.) As you work more with simple circuits using resistors in different arrangements with a given voltage source, try thinking of the voltage drop of a resistor as the voltage it "feels" when the circuit is energized.
Does adding resistors in series increase or decrease the overall resistance of a circuit?
Resistance in series adds together. two 100 ohm resistors in series are equivalent to one 200 ohm resistor. to make an equation out of it ( even though it is simple) you can say: Rtotal=R1+R2+R3...+Rn
How do you reduce 48 volts dc to 12 volts dc with resistors?
Yes. You can use a voltage divider. Say, for instance, one 1KOhm resistor in series with a 3KOhm resistor. Connect the 3k resistor to the 48 volts and connect the 1k resistor to ground. The 1k resistor will have 12 volts acress it. These resistors need to be at least 1 watt each as they are going to dissipate 0.576 watts and get warm. Now, if you attempt to pull power from the 1k resistor, note that regulation will be poor because the impedance of the load will go in parallel with the 1k resistor and change its value.
Which of the following are not types of home circuit?
It is hard to say when there is no "which of the following".
What control operates the fan motor?
Well, the fan switch... if it has, say, four settings, then the first three settings simply select which resistor the current runs through, and the fourth typically is a circuit with no resistor.
Why must a bulb be used in a circuit for safety reasons?
If we're talking about in-circuit diagnostics and measurements with the device powered on (like it oftentimes is with TV sets, or at least used to be), the light bulb serves a dual purpose:a) the bulb acts as a huge resistor capable of dissipating (as light) great quantities of power (unlike typical resistors which go up to say, 7W, a light bulb could be even 100W) - thereby protecting critical components from burningb) the second purpose is to be a kind of warning: in most typical devices, inrush current notwithstanding, the power consumption will be such that the bulb will not light up to its full brightness. If it does, it is usually indicative of a short circuit in the device (most likely in the power supply circuit, or the primary HV circuit such as those of CRT TVs)If we're, however, talking about ANY light bulb, even a LED light, typically included in the design, then its inclusion in the circuit is indicative: it simply informs the user that the device has power applied to it, and serves as a cautionary sign.
When the current will be short and open circuited?
Open circuit has no current, so does that mean any resistor in series with it, has no current ,so it can be ignored for analysis( v=ir so 0 current means 0 V) for finding lets say the Thevenin equivalent.? Now for Short circuit, do we ignore a resistor in series with the short, because current will take path of least resistance and ignore that resistor? Also can short circuit have voltage through it ?
Why is one bulb set up along a parallel circuit actually a series circuit?
In a series circuit, if you open a bulb, current loop will be broken. So, current cannot travel all the wayback, hence no output. But in a parallel circuit, current will be only shared with parallel circuit, but the loop remains closed even if you remove the bulb. So, no change occurs.
What will be the amps of a 12v 2amp circuit if there is a 12ohm resistor on it?
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
How does a three bulb circuit compare with the current when two bulbs are bypassed by a short circuit?
The current of one bulb (two bulbs shorted) would be about1 three times the current of three bulbs.1 I say "about" because resistance is a function of temperature, and running three times the current through one bulb will make that one bulb much hotter, increasing its resistance. It might also burn out the bulb.
What does the resistance in an electrical circuit limit?
Current flow. It's also worthy of noting that a resistor doesn't limit-by, it limits-to, and the current is dependent on the voltage. I[A] = U[V] / R[ohm] It's also worth to note, that the power flowing through said resistor with resistance R is I[A] * U[V] for DC circuits - helps to remember this well when picking appropriately-rated resistors for replacement. Example: let's say we have a 20-ohm, 2W resistor. If we place it in a circuit with 5V, we will get 5V / 20ohm = 250mA (0.25A) of current flowing through the resistor. The power the resistor will "see" is 250mA * 5V = 1.25W, so it's safe. But let's now put that same resistor in a 12V circuit. The current flowing will be 12V / 20ohm = 600mA (0.6A), and the power will be 600mA * 12V = 7.2W, so the resistor will burn.
What is on off switch?
Say it is a power circuit, a light bulb is bright from the battery, flowing through the wires and the light bulb. There is a switch controling the power that goes through, so if you switched the off switch off, the power will no longer be flowing through(the light bulb wouldn't be bright any longer). Say it is a power circuit, a light bulb is bright from the battery, flowing through the wires and the light bulb. There is a switch controling the power that goes through, so if you switched the off switch off, the power will no longer be flowing through(the light bulb wouldn't be bright any longer).
Is resistor an ohmic device in ac circuit?
Well, yes, sort of. "Ohm" is a measurement of resistance, so I would say yes. Although I'm not sure of 'ohmic' is really a word
What is the symbol used to represent a volt drop within an electric circuit?
You usually use V for volts. There can also be a subscript. Say for the voltage drop of a resistor could be called VR.
Why do you need a parallel circuit to measure voltage?
Voltage is a defined as a difference in potential. So to measure voltage, you need to look at the difference in potential between two different nodes in a circuit. For example, to know the voltage of a capacitor, you are looking at the difference in potential from one terminal of the capacitor to the other. Even if it is installed in a circuit. It is for this reason, that the measurement is across the circuit, or in parallel with it. One common point of confusion in voltage measurement is the way it is presented. Someone will say, that wire is at 5 volts. The "with reference to" part is often left off. We can say this because most circuits have a direct or implied ground, that all other voltages are referenced to. So the correct thing to say would be "that wire is at 5 volts to ground."
What happens when you disconnect a light bulb from a series cicuit?
Dear Wiki Questioner, When you disconnect a light bulb from a series circuit, the entire circuit is broken and no electricity can flow around it... so everything else on the circuit looses access to the power source! You can think of a series circuit as a relay race, where the runners are the bulbs and wires (and anything else that is connected to the circuit). If any one of the runners in a relay race is taken out of the race (say by a sprained ankle), the relay gets stuck and the team cannot complete the race (that is to say, the electricity cannot make a complete circuit). Of course, if you plug that runner back into the system, the race continues as usual!
