If we're talking about in-circuit diagnostics and measurements with the device powered on (like it oftentimes is with TV sets, or at least used to be), the light bulb serves a dual purpose:
a) the bulb acts as a huge resistor capable of dissipating (as light) great quantities of power (unlike typical resistors which go up to say, 7W, a light bulb could be even 100W) - thereby protecting critical components from burning
b) the second purpose is to be a kind of warning: in most typical devices, inrush current notwithstanding, the power consumption will be such that the bulb will not light up to its full brightness. If it does, it is usually indicative of a short circuit in the device (most likely in the power supply circuit, or the primary HV circuit such as those of CRT TVs)
If we're, however, talking about ANY light bulb, even a LED light, typically included in the design, then its inclusion in the circuit is indicative: it simply informs the user that the device has power applied to it, and serves as a cautionary sign.
There must be a current through the bulb in order for it to glow.
For a circuit to light a bulb, there must be a closed loop for the flow of electricity. This loop typically consists of a power source (e.g. battery), wires, a switch, and the bulb. When the switch is closed, the circuit is complete and electricity can flow through the wires to the bulb, causing it to light up.
The liquid must be a conductor of electricity in order for the bulb to light up. If the liquid does not conduct electricity, the circuit will not be completed and the bulb will not illuminate.
help :(
In a series circuit, if a light bulb is missing or broken, the circuit becomes incomplete, and the electrical current cannot flow. As a result, the other bulbs in the series will not light up. All components in a series circuit must be functioning for the entire circuit to operate.
What needs to be complete is the circuit from the battery to the bulb, then the other wire from the bulb to the other side of the battery.If it is from an outlet rather than a battery, the circuit starts and finishes with the live and neutral pins at the outlet.
You replace the light bulb...there must be a shortage in the circuit because of a bulb being blown out...
If one of the light bulbs in Gene's series circuit burns out, the entire circuit will break, causing all the lights to go out. This happens because, in a series circuit, the electrical current must flow through each component in sequence. When one bulb fails, it creates an open circuit, preventing electricity from reaching the remaining bulbs. To restore the lights, the burned-out bulb must be replaced or repaired.
When a bulb is added in parallel to a circuit with a single bulb, the resistance of the circuit decreases. This is because the existing bulb's operating point remains the same, due to the fact that Kirchoff's voltage law states that the signed voltages around a series circuit must add up to zero, with the two bulbs being their own series circuit. A consequence of this is that the voltage across both bulbs must be the same, i.e. that the voltage across the first bulb does not change. The second result of adding the bulb is that the current in the overall circuit increases. This is because the second bulb must pull some current in order to operate, yet we know that the voltage across the first bulb did not change. As a result, due to Ohm's law, the current through the first bulb did not change. And, finally, since Kirchoff's current law states that the signed sum of the currents entering a node is zero, the addition of a second load in parallel with the first load must, therefore, represent additional current.
Connect ammeter in series and voltmeter in parallel to the circuit
The light bulb must be connected in a closed circuit with a power source, such as a battery or electrical outlet, for it to light up. This means that the positive terminal of the power source must be connected to the positive terminal of the light bulb, and the negative terminal of the power source must be connected to the negative terminal of the light bulb. This allows the flow of electricity to power the light bulb and make it light up.
To light up the bulb, the two-way switch must be closed in the on position at both the 'Switch 1' location and the 'Switch 2' location. This will complete the circuit and allow electricity to flow to the light bulb, turning it on.