No, it is not possible to increase wattage in a resistor.
The resistor is designed with a specific wattage (power) rating, which is a function of its temperature coefficient and thermal transfer characteristics. Altering that would be more complex and costly than simply getting a resistor with a larger power rating.
As a quick solution, use four identical resistors, two in series, and those two sets in parallel. The equivalent resistance would be the same, but the power rating, assuming you maintain adequate separation, would be four times greater. Parasitic inductance and capacitance would be slightly different but, that should not matter, depending on the application.
it can't handle more power than that rated wattage. exceed the rating and it burns out.
In order to determine this, it will be necessary to find which resistor 'maxes out' at the lowest voltage. This can be found using the equation Vi=sqrt (Pi*Ri) for each resistor, where Pi is the power rating of resistor i and Ri is the value of resistor i. Once this is found, the power dissipation of each other resistor can be found using the equation Pi=(Vl^2)/Ri, where Vl is the voltage that maxes out the resistor which maxes out at the lowest voltage, and Ri is the resistance of each resistor. The equivalent power rating would then be the sum of the power dissipated across each resistor.
the voltage across that resistor will increase if it is in series with the other resistors. the current through that resistor will increase if it is in parallel with the other resistors.
There is no direct relationship.Power ('wattage') is a measure of the rate at which the resistor can dissipate energy; excessive power means that a resistor cannot dissipate energy fast enough to prevent its temperature becoming excessive -excessive enough to damage the resistor.As the rate at which a resistor can dissipate energy is determined by its physical size, a resistor's power rating(maximum continuous power it can handle without exceeding its rated temperature) depends on the physical size of the resistor.On the other hand, the resistance of a resistor is notaffected by its physical dimensions, as a resistor can be manufactured to any particular value of resistance for whatever physical size is necessary to achieve its rated power.If you know a resistor's rated power and its resistance, then you can calculate the maximum continuous current that resistor can handle without overheating (using the equation: power = current squared x resistance).
A possible/probable unit is Watts.
Resistors are rated in wattage so the lowest wattage rating will be the wattage of the series circuit. It will be able to handle that power any more and the lowest wattage resistor could be damaged and fail.Another AnswerWhen two or more resistors are connected in series, the resistor with the lowest resistance will operate at the highest power. If the power developed by a resistor exceeds its rated power, then the resistor may burn out.
it can't handle more power than that rated wattage. exceed the rating and it burns out.
How much power it can dissipate without being damaged.
there might be ways to get the power rating by measuring the size of the resistor. but as the physical size of the resistor increases, its power rating also increases..
The ohms tells you the resistance; the wattage tells you how much heat energy it can handle. Not that any resistor ever lived up to its specifications -- I always needed some type of heat sink. Bottom line -- yes.
Wattage.
cause its bad,replace with higher wattage rating.too much current !!
In order to determine this, it will be necessary to find which resistor 'maxes out' at the lowest voltage. This can be found using the equation Vi=sqrt (Pi*Ri) for each resistor, where Pi is the power rating of resistor i and Ri is the value of resistor i. Once this is found, the power dissipation of each other resistor can be found using the equation Pi=(Vl^2)/Ri, where Vl is the voltage that maxes out the resistor which maxes out at the lowest voltage, and Ri is the resistance of each resistor. The equivalent power rating would then be the sum of the power dissipated across each resistor.
The resistor is 1/3 of an ohm. A 9 volt drop across the resistor would cause a draw of 27 amps through the resistor. The wattage you would need for that resistor is at least a 243 watts.
There is no way to make the conversion. The wattage given as that of the resistor is only the amount of power it is dissipating. It's the heat the resistor is radiating. The resistor is said to be using or radiating 270.4 watts. (That's a lot of wattage! How hot would a 270 watt incandescent lamp get? Very hot.) A watt is sometimes called a volt-amp. That's because watts equals volts times amps. And it's easy to see how that works with an example including the approximately 270 watts set down in the question. As regards that approximately 270 watts specified, if the resistor was a 1 ohm resistor and had 270 amps of current flowing through it, the 270 watts would be the wattage the resistor would be radiating. If the resistor was a 270 ohm resistor and had 1 amp of current flowing through it, it would (also) be radiating 270 watts. See how that works? An unlimited number of variations on the theme exist. To find the resistance of the resistor, one of two things must be known in addition to the wattage the resistor is running at. Either the voltage across the resistor or the current flow through the resistor must be specified to "finish" the problem.
The wattage rating tells you how much electricity its consuming, most electrical appliances give this information.
Increase the voltage across the resistor by 41.4% .