No. The capacitor may improve its power factor by altering the effective reactive power of the machine, thus reducing the current drawn from the supply.
An ammeter's coil requires very little current for full-scale deflection (fsd). So, to measure a current above its fsd value, most of that current must be allowed to bypass the coil. This is achieved by placing a very low value shunt resistance in parallel with the coil ('shunt' is an archaic word for 'parallel').
ANSWERResistances in parallel reduce the total resistance to less than either, using the formula R = 1 / (1/R1 + 1/R2). Thus, R = 1 / (1/30 + 1/30 ), so R = 1 / ( 1/15 ), so R = 15.One way to remember how this works is that the two resistors provide two paths for electricity to flow, so the resistance will be less.Note: Inductances act the same way in parallel. Capacitors simply add in parallel. It is easy to remember these because an inductor is a coil, and placing them in series is like making a longer coil, which is how you increase the inductance of a coil. Capacitors can be made from two plates, and the capacitance increases with area, so placing two of them in parallel is equivalent to increasing the area of one.
In the common emitter configuration, gain is hFe or collector resistance divided by emitter resistance, whichever is less. Placing a capacitor across the emitter resistor effectively makes the emitter resistor less, for higher frequencies, so the gain is higher for higher frequencies. This creates a high pass filter, or a low cut filter, depending on what you want to call it.
Multiplexing.
Lights at home are connected in parallel. (Switches are connected in series with the lights in order to turn them on and off.) This way, each light receives the same voltage. Placing the lights in series would divide the voltage between the lights, reducing the power of each, and it would have the effect that one light burning out would cause all the others on the same circuit to stop working.
Cumlitive output
You charge a capacitor by placing DC voltage across its terminal leads. Make sure when using a polarized capacitor to place positive voltage across the positive lead (the longer lead) and negative voltage across the negative lead. Also make sure that the voltage you charge the capacitor to doesn't exceeds its voltage rating.
It depends on where the capacitor is located. If it is across the emitter resistor, then the gain of the CE amplifier will be higher at higher frequencies.Remember that gain in the CE amplifier is collector resistance divided by emitter resistance, or hFe, whichever is lower. Placing a capacitor across the emitter resistor will serve to make the effective resistance smaller at higher frequencies, resulting in increased gain, up to the limit of hFe.If this is not the intended location of the capacitor, then please restate the question and provide the capacitor location.
Continuity, resistance?
A voltage variable capacitor (VVC) is made by placing an intercalation compound between two electrodes of a capacitor. The VVC has a reservoir of an intercalant in proximity with the intercalation compound. The two materials are chosen from those known to exhibit the intercalation reaction. The extent of the intercalation reaction is controlled by applying a voltage to the intercalant reservoir and the intercalation compound. A variable capacitor is created by applying a signal to the device and appropriately controlling the ε of the device by using the input control voltages.
Placing another resistor in parallel to an existing resistor will lower the total resistance in the circuit. RParallel = 1 / Summationi=1toN (1 / Ri)
When batteries are connected in parallel, the voltage remains the same as the voltage of a single battery. This is because the positive terminals are connected together and the negative terminals are connected together, so the voltage across each battery remains constant.
They need to be supplied with a charge. You can light them by placing a redstone torch on an adjacent block, or you could link them with redstone dust to a lever, the level will provide a charge when 'on' and light the lamp.
Bug bites can be treated on children in a number of different ways: Washing the affected area with soap and water. Placing a cold compress such as a towel cooled with water to the affected area, to reduce the swelling. Not to scratch the affected area as it can become infected. Take painkillers Put an ice pack on the affected area.
It depends on what is wrong with the resistor. If it is damaged, replace it with the same type, value and power rating. If it is the wrong value and is not damaged, you can increase the value by placing another in series or reduce the value by placing another in parallel. If the resistor is variable type, you should be able to adjust it.
An ammeter's coil requires very little current for full-scale deflection (fsd). So, to measure a current above its fsd value, most of that current must be allowed to bypass the coil. This is achieved by placing a very low value shunt resistance in parallel with the coil ('shunt' is an archaic word for 'parallel').
No-one ever aims to reduce the power factor, the ideal power factor is equal to 1, and that is the maximum possible value. A load with a power factor of 0.7 draws 40% more current along the supply wires compared to a equal-power load with a power factor of 1. That means that the power loss in the resistance of the supply wires is doubled in the case of the poor power factor. Since the supply company receives no extra revenue for the lost power, it does not like this situation and sometimes penalises users with poor power factors with extra tariffs. The power factor can often be improved by placing a passive reactor in parallel with the load to draw off the reactive volt-amps (VAR or kVAR) so that the supply wiring sees a load with a good power factor. Normally a bad load like a motor draws inductive VARs and in this case it can be corrected with a parallel capacitor that draws an equal number of capacitive VARs. Looked at another way, the added capacitor 'tunes' the load to resonate at the supply frequency.