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Resistances in parallel reduce the total resistance to less than either, using the formula R = 1 / (1/R1 + 1/R2). Thus, R = 1 / (1/30 + 1/30 ), so R = 1 / ( 1/15 ), so R = 15.

One way to remember how this works is that the two resistors provide two paths for electricity to flow, so the resistance will be less.

Note: Inductances act the same way in parallel. Capacitors simply add in parallel. It is easy to remember these because an inductor is a coil, and placing them in series is like making a longer coil, which is how you increase the inductance of a coil. Capacitors can be made from two plates, and the capacitance increases with area, so placing two of them in parallel is equivalent to increasing the area of one.

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11y ago

Parallel resistance equivalents are calculated with reciprocals:

1/REQ = 1/R1 + 1/R2

In this case, 1/30 + 1/20 = 2/60 + 3/60 = 5/60

The reciprocal of 5/60 is 60/5, or 12 Ohm.

Remember, the parallel resistance equivalent will always be smaller than the smallest resistor value. The more resistors in parallel the lower the equivalent resistance.

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Q: What is the equivalent resistance for two 30 ohm resistors wired in parallel?
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