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What is the current in a circuit with 9 volts 3 ohms 2 ohms and 4 ohms?
Wiki User
∙ 6y ago
The current in the circuit will depend on how the three resistors are wired. Series? Parallel? Series parallel?
With the resistors in series, 3, 2 and 4 ohms will add to 9 ohms. As I = E/R, I = 9 V / 9 ohms = 1 A.
With the resistors in parallel, the 3, 2 and 4 ohm resistors will draw 3 A, 4.5 A and 2.25 A respectively, and the total current will be the sum of the branch currents, or 3 A + 4.5 A + 2.25 A = 9.75 A.
There are 3 different series parallel circuits possible, and more investigation will be necessary to solve for them.
Wiki User
∙ 6y ago
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What would the voltage be in a DC circuit if there were a current flow of 6 A and a resistance of 8 ohms?
Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...
How much current would an applied voltage of 10 volts cause through a resistance of 5 ohms?
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
What is the current in a 10v circuit if the resistance is 2?
If we apply Ohm's law, which is E = I x R and we have a voltage (E) of 110 volts and a current (I) of 10 amps, we can use the variation of the formula to solve. That variation is R = E / I and the resistance (R) is discovered by dividing the voltage by the current. R = E / I = 110 / 10 = 11 ohms
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
What is the resistance of an electric lamp that takes in a current of 0.40 ampere when 110 volts is applied?
Ohm's Law: Resistance is voltage divided by current 110 volts divided by 0.4 amperes is 275 ohms.
What would the voltage be in a DC circuit if there were a current flow of 6 A and a resistance of 8 ohms?
Ohms Law! E=IR Voltage equals current times resistance. Get out the old calculator...
How do you calculate ohms?
Very basically, simply divide the voltage by the amperage. Thsi is not for calculating Ohms of resistance, just Ohms. For example, a 9 volt battery that delivers 3 amps has 3 ohms. To calculate ohms of resistance we use the ohms law. This measures the difference in current flow in amps (amps/current is amount or volume of flow, volts is power pushing that current, sort of) and voltage. For instance, measure the amps and voltage at the source and record the ohms. Then record the same at the end point the difference in ohms is ohms of resistance. So, if we measure 10 volts and 2 amps at the source we have 5 ohms. at the end point we have 8 volts and 1 amp we have 8 ohms. therefore we have 13 ohms of resistance. 1 Determine current. Current is the flow of electricity measured in amps. For example a current has four amps in the circuit. 2 Determine voltage. Voltage is the difference in electrical potential from two points, measured in volts. For example, there is two-hundred volts in a circuit. 3 Divide voltage by current to calculate resistance. Resistance is measured in ohms. In the example, two-hundred volts divided by four amps equals fifty ohms. 4 To get ohms of resistance, measure the end point. at the endpoint we have 100 volts and 2 amps=50 ohms. therefore we have 100 ohms of resistance
If three cells that each have an emf 1.5 volts and an internal resistance of 2 ohms are connected in series to a resistor of 44 ohms what is the current through the resistor?
Taking the question at face value, the internal resistances will be treated like "real" resistors in the circuit. That means we have 3 batteries of 1.5 volts each connected in series with their 2 ohms + 2 ohms + 2 ohms of internal risistance, or 6 ohms of internal resistance. The 6 ohms of internal resistance acts in series with the 44 ohms of resistance stated as the value of the resistor. The total resistance is simply the sum of the two, or 6 ohms + 44 ohms or 50 ohms of total resistance. The batteries are connected in series, and their individual voltages are added to find total applied voltage. That means 1.5 volts + 1.5 volts + 1.5 volts or 4.5 volts will be the total applied voltage. Total current in the circuit (and through our 44 ohm resistor) will be the voltage applied divided by the resistance ( I = E / R), which, in this case, is 4.5 volts / 50 ohms which equals 0.07 amps. That's 7/100ths of an amp, or, in electronics speak, 70/1000ths of an amp, or 70 milliamps, or 70mA of current. The circuit is a series circuit, and that current, the total circuit current, will be flowing through each and every component of the circuit. That's what a series circuit means.
What is the current for 20 volts and 2 ohms?
1 amp.
How much current would an applied voltage of 10 volts cause through a resistance of 5 ohms?
10 volts applied to 5 ohms would cause a current flow of 2 amperes. Current = voltage divided by resistance.
What is the current in a 10v circuit if the resistance is 2?
If we apply Ohm's law, which is E = I x R and we have a voltage (E) of 110 volts and a current (I) of 10 amps, we can use the variation of the formula to solve. That variation is R = E / I and the resistance (R) is discovered by dividing the voltage by the current. R = E / I = 110 / 10 = 11 ohms
A circuit consists of two resistors of 5 ohms and 2 ohms connected in series if a current of 5 amps in the circuit the power dissipated in the 2 resisters will be?
Two resistors in series, one 5 ohms and one 2 ohms, with a current of 5 amperes, will have a power dissipation of 175 watts. Ohm's law: Voltage = current times resistance E1 = I R1 = (5) (5) = 25 volts E2 = I R2 = (5) (2) = 10 volts Power law: Power = current times voltage P1 = I E1 = (5) (25) = 125 watts P2 = I E2 = (5) (10) = 50 watts PT = P1 + P2 = 125 + 50 = 175 watts
What is the total power in a circuit with a current of 4 A and a resistance of 12 ohms?
In DC circuits, V = I / R, and P = V*I You can use these to get P = I^2 * R = (4)^2 * 12 = 192 watts.
Two 12 volt batteries in series one has 4 amp's another has 4 amp's they are connected across a 2 ohm load the current flowing in the circuit is?
Volts = Current x Resistance. You have 24 Volts divided by 2 ohms and the draw will be 12 amps. Your batteries will fail quickly if not spectacularly.
What is the current when the voltage is 18 volts and the resistance is 6 ohms?
V=i*r=2*6=12v
What is the total resistance of three resistors in parallel with values of 2 ohms 8 ohms and 14 ohms?
Current, by Ohm's Law, is voltage divided by resistance, so, 18 volts divided by 2 ohms is 9 amperes.
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
