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If we apply Ohm's law, which is E = I x R and we have a voltage (E) of 110 volts and a current (I) of 10 amps, we can use the variation of the formula to solve. That variation is R = E / I and the resistance (R) is discovered by dividing the voltage by the current. R = E / I = 110 / 10 = 11 ohms
What else can I help you with?
What is the affect of a series circuit on current?
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
How is total resistance in a series circuit determined?
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.
How will a current change if the resistance of a circuit remain constant while the voltage across the circuit decreases to half its original value?
Voltage = resistance X current abbreviated,V = C * RIf you halve the voltage of the current, then the other side of the equation must also be halved; therefore, you get:(1/2)V=(1/2)(C*R)which is the same as:(1/2)V=(1/2)(C)(R)which means that either the current or the resistance must be halved as well, and because the resistance stays the same, then the current is halved.
What is the affect of a series circuit on current?
by adding the the resistances in series the total resistance of the circuit increses and thus the crunt flowing in the circuit decrese. Ans 2 . the current in series circuit of constant resistance will always be the same . It will not effect the current .
What is the current in a circuit that has a resistance of 30 ohms and a power of 2 watts?
To find the current in the circuit, you can use the formula: Power = Current^2 * Resistance. Given the values, you can rearrange the formula to solve for current: Current = sqrt(Power / Resistance). Plugging in the values, you get Current = sqrt(2 / 30) which simplifies to approximately 0.27 amperes.
In series circuit is currant change with change in resistance?
V=IR where V is voltage, I is current and R is resistance. You want to know what the current will be in a series circuit based on the resistance. You need to know the voltage as well as the resistance, gives you the equation as follows I=V/R So if you have 10 volts and a 1 ohm resistor, the current will be 10 amps. If you increase the resistor to 10 ohms, your current will then be 1 amp. In a parallel circuit, the resistance is equal to the sum of the inverse. For example. If I have two resistors of 2 ohms each in parallel, the equation would be 1/2 + 1/2 = 0.5 + 0.5 = 1 In that particular instance, your current would increase.
Is power directly proportional to resistance?
No, power is not directly proportional to resistance. The power dissipated in a circuit is given by P = I^2 * R, where I is the current flowing through the circuit and R is the resistance. This means that power is proportional to the square of the current but linearly proportional to resistance.
What is the power of a ciruit with 10 ohmns 10 volts and 2 amps?
Well, first of all, if the resistance of the circuit is 10 ohms and you connect 10 volts to it,then the current is 1 Amp, not 2 . So either there's something else in your circuit thatyou're not telling us about, or else the circuit simply doesn't exist.-- If you connect some voltage to some resistance, then the resistance heats up anddissipates (voltage)2/resistancewatts of power, and the power supply has to supply it.-- If there is some current flowing through some resistance, then the resistance heats up anddissipates (current)2 x (resistance)watts of power, and the power supply has to supply it.-- If there's a circuit with some voltage connected to it and some current flowingthrough it, then the resistance of the circuit is (voltage)/(current) ohms, the partsin the circuit heat up and dissipate (voltage) x (current) watts of power, andthe power supply has to supply it.There's no such thing as "the power of a circuit". The power supply supplies thecircuit with some amount of power, the circuit either dissipates or radiates someamount of power, and the two amounts are equal.
Why is there no flow of electric current?
There are two possible causes: 1. The circuit has no Voltage applied to it. 2. The resistance of the circuit is INFINITE.
What is the power of a parallel circuit with a resistance of 1000 and a current of0.03 a?
I don't know what the parallel circuit has to do with it. You've onlygiven me a resistor and the current through it.When 0.03A of current passes through a 1,000Ω resistor, the resistordissipates energy at the rate of 0.9 watt.
What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.60 V / 2 A = 30 Ω
How is total resistance in a series circuit determined?
Series circuit: The total voltage is the sum of the voltage on each component. The total resistance is equal to the sum of the resistance on each component. The total current is equal in every component.
How do I design a voltage divider circuit that has 2 VDC 5 VDC and 8 VDC available with a 10 VDC source?
Without knowing permissible current draw by the divider or its maximum power dissipation the actual resistor values cannot be determined, but the ratios of the resistor values can be determined from the required voltage drops.The divider will be composed of 4 resistors starting at the 10VDC rail:2VDC drop, ratio = 2V/10V = 0.23VDC drop, ratio = 3V/10V = 0.33VDC drop, ratio = 3V/10V = 0.32VDC drop, ratio = 2V/10V = 0.2Therefore you will need 2 resistors (R1 & R4) that are 0.2 * the total resistance of the voltage divider and 2 resistors (R2 & R3) that are 0.3 * the total resistance of the voltage divider.But as stated at the beginning you can get no further without additional requirements being specified.
You are just asking that let us assume you have connected 2 or 3 resistors in a circuit and the current flowing through the circuit and from all the resistors will be same but how?
If the resistors are connected in series, the total resistance will be the sum of the resistances of each resistor, and the current flow will be the same thru all of them. if the resistors are connected in parallel, then the current thru each resistor would depend on the resistance of that resistor, the total resistance would be the inverse of the sum of the inverses of the resistance of each resistor. Total current would depend on the voltage and the total resistance
In a circuit with a 6 V battery hooked up to a 3 Ohm light bulb what does the current measure?
2 amperes (current = voltage/resistance)
