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What is the resistance in a circuit that has a voltage of 60 V and a current of 2 A?
Wiki User
∙ 15y ago
Ohm's law is V = I·R. You know V and I, so you can calculate R using R = V/I.
60 V / 2 A = 30 Ω
Wiki User
∙ 15y ago
Wiki User
∙ 14y agoA circuit with a voltage of 60 volts and a current of 2 amperes has a resistance of 30 ohms.
Ohm's law: Voltage equals resistance times current.
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8 If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V the current flowing through the circuit is?
There is a simple equation relating voltage (properly potential difference), current and resistance: V=IR Where V=potential difference, I=current and R=resistance So to answer: I=60/12 I=5
How much current flows through a lamp with a resistance of 60 Ohms when the voltage across the lamp is 12 V?
The relation between resistance R, Current I and voltage V is: R= V/I Therefore: 60 = 12 / I <=> I = 12 / 60 = 0.2 amp
Is the current always the same in parallel circuits?
An example of a parallel circuit would be the light bulbs in track lighting. Each bulb has the same voltage applied. The current through any one light bulb equals the voltage divided by the resistance of the bulb. The current also equals the wattage of the bulb divided by the voltage. So if all the bulbs had exactly the same resistance the current would be the same. However, your question says "always" so in general the answer is no. In the case of track lighting if you had a 60 watt bulb in parallel with a 120 watt bulb, the 60W bulb would draw 1/2 amp and the 120W bulb would draw 1 amp. The sum of the current flowing in a parallel circuit equals the sum of the current in each leg of the circuit.
What is the resistance of a lightbulb using Ohm's law?
By Ohm's law, resistance is voltage divided by current, so the resistance of a light bulb can be measured by observing the voltage across it simultaneously with observing the current through it. Interestingly, the hot resistance is significantly different that the cold resistance, so measuring resistance with an ohmmeter will not give a meaningful resistance. This is because the resistance of a light bulb has a positive temperature coefficient. Take a typical 60 W 120V light bulb, for instance... Its cold resistance is about 16 Ohms. Calculate current and power at 120 V and you get 7.5 A and 900 W. The truth is that at 60 W, the bulb pulls 0.5 A and has a resistance of 240 Ohms.
How much voltage does a line with resistance of 10 ohms and a current of 20 amps?
V = i*r v = 2 * 60 v= 120v
If the resistance of an electric current is 12 ohms and the voltage in the current is 60 V the current flowing through the circuit is?
..using the formula Voltage(V)=Current(I) * Resistance(R) .. we can get the result ...current will be 5 Ampere
8 If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 V the current flowing through the circuit is?
There is a simple equation relating voltage (properly potential difference), current and resistance: V=IR Where V=potential difference, I=current and R=resistance So to answer: I=60/12 I=5
If the resistance of an electric circuit is 12 ohms and the voltage in the circuit is 60 volts the current flowing through the circuit?
V = I times R where V = voltage, I = current and R = resistance. Further, I = V / R.As I = V / R, I = 60 /12 = 5 amps.V=IR , where V=60 volts R=12 ohms so I = V/R = 60/12 = 5 Amp.
What is the resistance in a circuit that has a voltage of 60 and a current of 2?
since it is a simple ckt here we can go for ohm's law according to which voltage(v)=current(I)*resistance(R), so, R=V/I In the problem given, V=60, I=2A on substuting in the formula we get R=60/2 i.e. R=30 ohm inform.mayaprasad@gmail.com
If the resistance of an electric current is 12ohms and the voltage is in the current is 60 v the current flowing through the curcit is?
V=IR V=Voltage I=Current R=Resistance I=V/R 5 Amps.
How much current flows through a lamp with a resistance of 60 Ohms when the voltage across the lamp is 12 V?
The relation between resistance R, Current I and voltage V is: R= V/I Therefore: 60 = 12 / I <=> I = 12 / 60 = 0.2 amp
What is the current in an ac circuit with 120volts and a 60watt light bulb?
Power = Current * Voltage Current = Power / Voltage Current = 60 W / 120 V Curretn = 0.5 A
How can you calculate current drawn in 60 HZ circuit?
You need to divide the supply voltage by the impedance of the load. The impedance of the load is the vectorial sum of its resistance and reactance, where reactance is proportional to frequency.
If resistance is constant and voltage increases what happens to current?
You have it backwards, the resistance controls the current not the current controls the resistance. I = E/R . Your question should read, "If the voltage is constant and the resistance in the circuit is increased what happens to the current?" Say the voltage is 120 volts and the resistance is 30 ohms, I = 120/30 = 4 amps. Now we double the resistance to 60 ohms, then I = 120/60 = 2 amps. So now you can see if you increase the resistance the current drops.
If the resistance of an electric circut is 12 ohms and the voltage in the circut is 60V the current flowing through the circut is?
Ohm's law states that V=IR, that is, Voltage is equal to the current through the circuit times the resistance.Manipulating this equation gives I=V/R, so I=60/12 = 5 A
What is the current in an ac circuit with 120-volts and a 60 -watt light bulb?
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
What is the current in an ac circuit with 120- volts and a 60-watt light bulb?
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
