In this case, to get the equivalent resistance, first you use the parallel formula (1/R = 1/R1 + 1/R2) to calculate the equivalent resistors in parallel. Then you calculate the series resistance of this combination, with the other resistor.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
30 ohms.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.
if the circuit is a series circuit (all loads wired in a single line , one after the other ) then the current will be the same in any part of the circuit . if there are several different paths for the current to take , then each path will carry a different percentage of the total current . when each of these different current values are added together , they will equal the total supplied current.
First, the question doesn't say if the resistors are in series or parallel, or series-parallel. Second, the current given is zero, which can only be true if the circuit has no applied voltage. (It's turned off.) This will be true regardless of the circuit configuration. We were told the "middle resistor" in the question, but that's still a bit "iffy" for us. We need to know how it's wired. Since we don't, we'll look at the three possibilities. If all three resistors are in series, the total resistance is the sum of all the resistors. It's this: Rt = R1 + R2 + R3 ... or Rt = 3 + 3 + 3 = 9 ohms A shortcut can be applied when identical resistors are in series. The total resistance will be the value of one multiplied by the number of them in series. In this case, 3 x 3 = 9 ohms. If the resistors are all in series, the total resistance is this: Rt = 1 / ( {1 / R1} + {1 / R2} + {1 / R3} ...) or Rt = 1 / ( {1/3} + {1/3} + {1/3}) = 1 / (3/3) = 1 / 1 = 1 ohm We can shortcut that when we have identical resistors in parallel. The total resistance will be the value of one of them divided by the number that are in parallel. So we'd have: Rt = (3 / 3) = (1 / 1) = 1 ohm If two are in series with one across them in parallel, the total resistance is found for each individual parallel branch and then the parallel branches (which have been reduced to a single equivalent resistance) can be taken into the parallel resistors equation and the total equivalent resistance calculated. In this case, one branch has two series resistors of three ohms. The total for that branch is 6 ohms, which we find by just adding them up. Now we have a 6 ohm (equivalent) resistor in parallel with a 3 ohm resistor. Take them into the equation and calculate. It's like this: Rt = 1 / ({1/6 } + { 1/3 }) = 1 / ({ 1/6 } + { 2/6 }) = 1 / ( { 3/6 }) = 1/ (1/2) = 2 ohms
It represents that two resistors are connected in parallel.
Resistors are wired in series when they are connected in a line. The current flows through the resistors one after the other.
What do you mean by a 'parallel delta' circuit -is there such a connection.
When resistors are wired in series, their resistances are added to find the total resistance. If they are run in parallel, or series-parallel, the formula is different
The current in the circuit will depend on how the three resistors are wired. Series? Parallel? Series parallel? With the resistors in series, 3, 2 and 4 ohms will add to 9 ohms. As I = E/R, I = 9 V / 9 ohms = 1 A. With the resistors in parallel, the 3, 2 and 4 ohm resistors will draw 3 A, 4.5 A and 2.25 A respectively, and the total current will be the sum of the branch currents, or 3 A + 4.5 A + 2.25 A = 9.75 A. There are 3 different series parallel circuits possible, and more investigation will be necessary to solve for them.
Two resistors wired in parallel means that both resistors are soldered together to equal the value of a smaller resistor value. Both resistors will be connected to the same line on the circuit board and then both will terminate on the same final line they are assigned to. Thus, a pair of 100k ohm resistors can take the place of one 50k ohm.
What would the measured ohms be for two 100 ohm resistors wired in series? Two 100 ohm resistors wired in series measure 200 ohms.
You get more voltage and current capacity.
30 ohms.
Two resistors wired in series (no mater if they have the same resistor value or not) will always have the same amount of current flowing through them. Therefore, the current flowing through the second resistor will be equal to the current flowing through the first one. The current through every component in a series circuit is the same. The voltage across every component in a parallel circuit is the same.
6 separate 18kOhm resistors wired in series make a total resistance of:18k+18k+18k+18k+18k+18k which is 108 kOhm.6 separate 18kOhm resistors wired in parallel make a total resistance of:1/[(1/18k) + (1/18k) + (1/18k) + (1/18k) + (1/18k) + (1/18k)] which is 3 kOhm.
When resistors of the same value are wired in parallel, the total equivalent resistance (ie the value of one resistor that acts identically to the group of parallel resistors) is equal to the value of the resistors divided by the number of resistors. For example, two 10 ohm resistors in parallel give an equivalent resistance of 10/2=5Ohms. Three 60 ohm resistors in parallel give a total equivalent resistance of 60/3 = 20Ohms. In your case, four 200 Ohm resistors in parallel give 200/4 = 50 Ohms total.