A: LED follows an exponential curve just like a regular diode. However their make up moves the forward voltage from 1.8 volts to 3.2 volts and higher this differs from a regular diode where is the forward voltage is around .6 to.7 volts. Because of the higher voltage across these devices they cannot dissipate much power.
The forward voltage of an LED is the voltage that must be applied across the leads of an LED, anode to cathode, in order for the LED to function and turn on.
when a LED is subjected to a high voltage it will heat up and burn the internal junction, which will leave the LED open circuit.
cut in vge si .6&ge 0.2
The forward biased voltage drop of a diode depends on the type of diode and the current through the diode. A typical silicon diode will exhibit a voltage drop between 0.6v and 1.4v depending on current. An LED might range from 2v to 3v. A germanium diode might go a low as 0.2v. Bottom line; it varies.
The protecting resistor is put in series with the LED so that you have a voltage divider - the supply voltage is split across the LED ( max 0.6v) and the remainder across the protecting resistor. So if your supply is 6volts, 5.4v will be across the resistor,
A: That resistor is there to limit the current to the LED it can be any value if the voltage is decreased or increased or no resistor if the voltage across the led is equal to the forward voltage drop.
LED stands for light emitting diode. If it is polarized correctly, and working correctly, it will be emitting light. If it is burnt out, or voltage has been applied backwards to it, it will not.
The forward voltage of an LED is the voltage that must be applied across the leads of an LED, anode to cathode, in order for the LED to function and turn on.
A; a LED can have a voltage of 1.8v to 5 or higher voltage whites and red are usually in the low voltage while green and blue are int he range of higher voltage
There's no set voltage that'll run ALL led's, it'd depend on the particular led.
The voltage drop across an LED varies, but is typically around 2 volts.
when a LED is subjected to a high voltage it will heat up and burn the internal junction, which will leave the LED open circuit.
An LED usually has a resistor connected in series with it because an LED (light emitting diode) is not linear in current to voltage (like a resistor) and has to be operated within specified current and voltage conditions. In most circuits the supply voltage is higher than the forward voltage of the LED so the LED would burn up from too much current without a current limiting resistor in series. The resistor sets the voltage and current to a good operating point (voltage and current) for the LED by dropping some voltage across it. The operating point varies depending on the size, type and manufacturer of an LED so the LED's data is used to select the right resistor size for a given voltage source.
A LED has a forward voltage drop dependent on it's composition. It is fairly constant within a small range of current flow. If the voltage is too high and the current is not limited, the LED will burn out. The brightness can be varied by varying the available current, but the voltage across the LED remains virtually the same.
LED needs a voltage drop, like Vled=0.7V (see datasheet of the component) in order to start conducting. A voltage below 0.7V the led dont conduct therefore it wont emit any light.
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