I think that the anwer would be 40 ohm's
circut of an amplifier
It is simple LEDS do need a definite voltage drop to work must have a minimum current to operate. for a 9v battery source and a LED of 3.2v operating at 20ma the solution will be 9v-3.2=5.8v therefore to limit the current to 20ma a resistor of 5.8v/0.02=290 ohms not such an animal so a 270-300 ohms will work. Final note make sure that the LED power is not exceeded 3.2v x0.02ma=63 mw
Series - parallel circut
It is called the loopdie loop circut.
when the switch the emitter-base junection is an opnd circut and heance the value of input or base curent is zero.
circut
A resistor is a special load in a circuit that slows down the flow of electrons. Resistors are passive electrical components that resist the flow of current, causing a voltage drop across them and dissipating energy in the form of heat. This property allows them to control the amount of current in a circuit and protect components from damage due to excessive current flow.
It heats up by opposing the flow of charge through the circui- Apex
current will increase
the amount of power going to the object will will cause the circut breaker to blow. if the object is not connected to a breaker then the object will catch on fire.
Ohm's law states that V=IR, that is, Voltage is equal to the current through the circuit times the resistance.Manipulating this equation gives I=V/R, so I=60/12 = 5 A
A voltmeter measures the voltage present in the circut. Voltage is the amount of energy available to push charges through an electric circut.
Parallel Circut
fuse
move the magnet faster
your mom is so fat she cloggs up all the paths for the current
Circuit means a current of electricity going thruogh a power source and resistance.