8x12=96
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
First thing voltage does not flow current does. Voltage is the potential or pressure needed to make the current flow. Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. To make the current flow you have to adjust the resistance of the circuit and that would be the water in this case. Salt added to water will make the water conductive so the resistance can be adjusted thereby making the current rise or fall depending on the water solution's resistive properties. The equation that you should consider using is Amps = Volts/Resistance.
When a transformer is initially connected to a source of AC voltage, there may be a substantial surge of current through the primary winding called inrush current. Inrush current can be up to ten times higher than the continuously needed current because there is low initial resistance.
Resistance Resistance is one of the biggest factors affecting power flow in a network. Resistance impedes the flow of electricity. Every element of an electric network has some amount of resistance. The electricity and power of a network will follow the path of least resistance. In order to calculate the power of a resistive element, such as a resistor, at least two of three things need to be known: the resistance of the element, the voltage across the element and/or the current through the element. The power of an element can be calculated either by voltage times current; current squared times resistance; or voltage squared divided by resistance. Load The type of load attached to a network will affect a networks power flow as well. A resistor connected as a load to a network will generate a constant power flow. An electric motor will generate a very high power during startup due to the high current needed to start the motor. As the motor reaches its normal speed, the power needed will drop and stabilize to a fairly constant state. The power needed from the network will remain constant as long as the motor's speed and load are constant. If the motor's load increases, the power needed from the network will increase. Circuit Type There are two basic types of circuits, series and parallel circuits. In a series circuit, all of the current flows through one load. In a parallel circuit, there are multiple paths for the current to supply multiple loads. Each branch gets a fraction of the current depending on the resistance of each branch element. This also means that each branch will use a different amount of power.
use Ohm's law: to drop 2 volts, V = I x R 2 = current x resistance resistance = 2 / current. So you need to know the current
18volts
12 voltage
Voltage across a resistance = (resistance) x (current through the resistance) =4 x 1.4 = 5.6If the ' 1.4 ' is Amperes of current, then the required voltage is 5.6 volts.
18 volts
Work it out yourself -the equation is: voltage = current x resistance.
Ohm's Law: Current = voltage divided by resistance. 5 V divided by 12 KΩ is 416 2/3 ma
Voltage, current, or power. You need two out of the three.
4
Using Ohm's law, you can find voltage if power is given. The equation needed to solve for power is P(Power)= Voltage(E) x Current(I). Ohm's Law describes the relationship between resistance, current, power, and voltage.
Where: V = Voltage (Volts), A = Current (Amps) and R = Resistance, (Ohms)Here are a few easy and related equations.V = A * RR= V / AA = V / RSo we have R=3 and A =6 and using the V=A*R equation we getVolts = A(6)*R(3) = 18 Volts.
A: That will happen anytime the voltage source is not able to provide the power needed for the load. If the load exceed the power available from the source the voltage will be reduced as IR drop from the source
First thing voltage does not flow current does. Voltage is the potential or pressure needed to make the current flow. Current is directly proportional to the applied voltage and inversely proportional to the resistance of the circuit. To make the current flow you have to adjust the resistance of the circuit and that would be the water in this case. Salt added to water will make the water conductive so the resistance can be adjusted thereby making the current rise or fall depending on the water solution's resistive properties. The equation that you should consider using is Amps = Volts/Resistance.