Ohm's Law: Current = voltage divided by resistance.
5 V divided by 12 KΩ is 416 2/3 ma
0.0004A
0.001
2.4ma
420.67wa
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
If there's nothing else between the ends of the resistor and the power supply, then the voltage across the resistor is 24 volts, and the current through it is 2 amperes.
The reason why resistor voltage decreases while a capacitor discharges is because the resistor acts like a source of electrical energy. As the capacitor discharges, it draws energy from the resistor, which causes the voltage across the resistor to decrease. This is because the capacitor is acting like a drain, and is taking energy out of the resistor, thus causing the voltage across the resistor to decrease. The resistor and capacitor work together in order to create a discharge circuit. This is done by connecting the capacitor to the resistor, and then to a voltage source. The voltage source supplies the energy to the resistor, and then the resistor transfers this energy to the capacitor. As the capacitor discharges, it takes energy from the resistor, which causes the voltage across the resistor to decrease. In order to understand this process better, it is important to understand the basics of Ohm's Law. Ohm's Law states that the voltage across a resistor is equal to the current through the resistor multiplied by the resistance. As the capacitor discharges, it takes energy from the resistor, which means that the current through the resistor decreases, and therefore the voltage across the resistor will also decrease.
No. If a voltage is applied across a resistor, a current flows through it.
The resistor is 1/3 of an ohm. A 9 volt drop across the resistor would cause a draw of 27 amps through the resistor. The wattage you would need for that resistor is at least a 243 watts.
The correct question is what is the voltage drop across a resistor or the current flowing through the resistor using Ohm's Law where Voltage = Current x Resistance
Current flows in loops, voltage drops across elements. With relation to current, what flows in, must flow out, so no, current is not dropped across a resistor, it flows through a resistor and voltage is dropped across the resistor.
Volt across a resistor = resistance x current through the resistor.
Normally through the resistor's internal construction. It flows through any part of the resistor that has low resistance- be it anywere. And then there's this. It might be that one should consider that current flows through a resistor and voltage is dropped across a resistor. Perhaps this is where the question began. The former is fairly straight forward. The latter can be vexing. Voltage is said to be dropped across a resistor when current is flowing through it. The voltage drop may be also considered as the voltage measureable across that resistor or the voltage "felt" by that resistor. It's as if that resistor was in a circuit by itself and hooked up to a battery of that equivalent voltage.
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
A resistor drops both voltage and current, however the term "drop" is generally used to indicate a voltage or current drop across the device, so it is more correctly stated that a resistor drops voltage, by allowing the current in the circuit to decrease.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
120v
Ohm's law states that the voltage across a resistor is the product of the current times the Resistance or V=I x R (I times R). V is Voltage, R is Resistance, and I is Current or Amperage. So if the Voltage is doubled and Resistance stays the same, the Current will be doubled.
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).