The question is incomplete without the voltage across the resistor.
For example:
if V (Voltage across 500 ohm resistor) = 5 Volts,
then,
Current, I = 5/500 Ampere = 0.01 A.
The current would be about 20 volts.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
A 120V power supply connected to a 30 Ohm resistor will produce 120/30 or 4 amps of current.
Ohm's law: Volts = amps times ohms In the case of a 4 ohm resistor with 1.5 amps of current, the voltage is 6 volts.
What is the amount of current flowing through the resistor? Voltage drop is dependent on the current. Ohm x Amps = Voltage drop
The current would be about 20 volts.
1amp
6
If they're in parallel, then each resistor acts as if it were the only one,and the presence of any others is irrelevant.The current through the 60-ohm resistor is I = E/R = (120/60) = 2 amperes.
The 5 Ohm resistor will have more current passing through it than the 10 ohm resistor. Since the resistors are in parallel the Voltage across each resistor is the same. Power or the amount of heat in terms of the question can be derived from Power = Voltage * Current. Ohm's law tells us that the current flowing through a resistor is equal to the Voltage across the resistor divided by the resistance. The formula for power is then the Voltage * Voltage / Resistance. Since V^2 / 10 is smaller than V^2 / 5 we know that the 5 ohm resistor will always have more power dissipated than the 10 ohm resistor.
It depends on the voltage applied across it. But the maximum current is limited by the power-rating of the resistor (power divided by the square of the voltage).
E/R=I. 100/50=2 amps.
500 ohm resistance is widely used to convert 4-20 ma current signals generated by a wide range of sensors into voltage signals. It provides 2 to 10 volts to the device. E=IxR.
The current through the 40-ohm resistor is ( E / R ) = (120 / 40) = 3 amperes.The current through the 40-ohm resistor doesn't depend on the 120-ohm resistor. It's the samewhether the 120-ohm is there or not. It would also be the same if there were any other resistor,with any other resistance, connected in place of the 120-ohm resistor. It would also be the sameif there were 3,000 more resistors in parallel, with all different values of resistance (as long asthe whole conglomeration didn't exceed the capabilities of the power source).
Ohm's law: current equals voltage divided by resistance, so a 203 ohm resistor would draw 0.57 amperes from a 115 volt power supply.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes. If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
If they're in parallel, then the resistors have no effect on each other. The current through each one is the same as it would be if the others were not there at all. The current through the 120Ω resistor is 120 volts/120Ω = 1 Ampere. The 60Ω and the 40Ω are red herring resistors.