If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in series, the current in the circuit is 1.0 amperes.
If a 9.0 volt battery is connected to a 4.0-ohm and 5.0-ohm resistor connected in parallel, the current in the circuit is 0.5 amperes.
A resistor does not only decrease current in a circuit it can also reduce tension(voltage) if connected in series.
4.8 ohms
3 ampere
It depends on the purpose for installing the resistor. If the intent is to decrease current flow, the resistor must be connected in series with the load. If the purpose is to increase current flow, the resistor must be connected in parallel with the load. To connect a resistor in series, connect the resistor to one side of the power source, in line with the load. This will decrease circuit current flow. To connect a resistor in parallel, connect the resistor between the positive and negative sides of the power source, which will effectively connect the resistor across the load . This will increase current flow through the circuit. However, before connecting a component in parallel, make sure the increase in current flow will not exceed the current rating of the circuit or fuses/breakers will blow.
True
A resistor does not only decrease current in a circuit it can also reduce tension(voltage) if connected in series.
4.8 ohms
yes... this is possible if a diode i connected in reverse bias with a battery and a resistor for example. A diode in reverse bias means its anode will be connected to positive terminal of the battery and its cathode to the negative terminal of the battery. In such a case, minimal current flows through the circuit which can be neglected.
in a flashing led circuit connected in series
Ohm's laws says it will be 1.5 vdc divided by 330 ohms.
3 ampere
A circuit with a 2 ohm resistor and a 4 ohm resistor in series with a 12 volt battery will have 2 amps flowing through each resistor. The current is the same in each resistor because they are in series, and a series circuit has constant current throughout.
the current flowing in will be low
:) It's connected together
When a resistor is added the current goes down, that is expressed in the equation current= voltage/ resistance
V = 6 V R = 10 Ohm I = V/R = 0.6 A
2 A (amperes)