It depends on the purpose for installing the resistor. If the intent is to decrease current flow, the resistor must be connected in series with the load. If the purpose is to increase current flow, the resistor must be connected in parallel with the load.
To connect a resistor in series, connect the resistor to one side of the power source, in line with the load. This will decrease circuit current flow.
To connect a resistor in parallel, connect the resistor between the positive and negative sides of the power source, which will effectively connect the resistor across the load . This will increase current flow through the circuit. However, before connecting a component in parallel, make sure the increase in current flow will not exceed the current rating of the circuit or fuses/breakers will blow.
if not disconnected you will measure the resistance of the circuit in parallel with the resistor.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.
It is used to vary the voltage/current flow in a circuit.
a resistor
When the frequency is zero(i.e when dc power is supplied), capacitor is open is treated as open circuit having infinite resistance.
By installing the varialble resistor in the circuit,the constant dc voltage would change .
I wanna use resistor , capacitor and amplifier 7173 for switch alarm circuit. How can i choice resistor and capacitor value because i wanna use 24V DC.
If the 3-ohm resistor is the ONLY thing in the circuit, then the current flowing through it is (12 volts)/(3 ohms) = 4 amperes. If there are other things in the circuit besides the resistor, then the current depends on all of them.
The resistor in the snubbing circuit is there to minimize the reverse EMF spike that occurs when a DC inductive load, such as a relay coil or other electromagnet is released. Opening the snubbing circuit will expose the driving circuit to high voltage transients that can damage it.
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A resistor, by itself, can not convert DC into AC.
if not disconnected you will measure the resistance of the circuit in parallel with the resistor.
when we replace the resistor with a capacitor ,the current will flow until the capacitor charge when capacitor will fully charged there is no current through the circuit because now capacitor will act like an open circuit. for more info plz E-mailt me at "zaib.zafar@yahoo.com"
The same as the time constant of a 2.7 microfarad capacitor and a 33 ohm resistor connected in series.
Fluorescent lights work just fine on DC voltage, BUT one needs a current limited power source to stabilize the circuit against the negative resistance of the gas discharge. This can be done with either a resistor or an electronic circuit. The resistor solution is too lossy because excess voltage from the dc csupply has to be converted to heat across the resistor. Electronic switching supplies could supply a fluorescent light with a dc voltage and current without the losses. But that's technological overkill and most circuits still supply AC.
The current depends on the total effecvtive resistance of everything connectedacross the battery.If the resistor is the only component there, then the current is E/R = 12/3 = 4 amperes.