Ohm's law: current equals voltage divided by resistance, so a 203 ohm resistor would draw 0.57 amperes from a 115 volt power supply.
Need more information - a typical regulated power supply would include dozens of resistors, each for one of several different reasons. Which resistor are you asking about?
You just stated that the voltage across the resistor is 15 volts, so that's your answer ! If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts. The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.
A cement resistor is typically used as a power resistor (a resistor whose power rating is greater than 1 W).
A variable power supply is one whose output voltage (or current) can be adjusted and therefore set to a desired figure. They are used in development and design odf circuits, eliminating the need for possibly many power supplies of different output voltages. Once a circuit is connected to it, the output would not normally be changed.
They are resistance connected in parallel with high voltage power supply for the purpose of discharging the energy stored in filter capacitance when the equipment is turned off.
Need more information - a typical regulated power supply would include dozens of resistors, each for one of several different reasons. Which resistor are you asking about?
Injectors that have a resistor in the power supply are called
The question has just stated clearly that the applied voltage is 12 volts DC.Provided that the power supply is capable of maintaining its output voltage while supplying some current ... i.e. that the effective internal resistance of the power supply is small ... and that the 2.7 ohm resistor is the only external element connected to the power supply's output, the voltage across the resistor is exactly 12 volts DC.The current through the resistor ... supplied by the 12 volt DC supply ... is 12/2.7 = 4.44 Amperes (rounded).The power dissipated by the resistor ... supplied by the DC supply ... is 122 / 2.7 = 53.23 watts !
You just stated that the voltage across the resistor is 15 volts, so that's your answer ! If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts. The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.
a power supply (eg: battery) and a load (eg: resistor) even a piece wire shorting two terminals of the power supply is a closed circuit
A resistor determines the speed that electrical energy is spent, the power. Without it, the supply is spent immediately and cannot be stored.
A 120V power supply connected to a 30 Ohm resistor will produce 120/30 or 4 amps of current.
When a resistor and an inductor are both connected to an AC supply, the current in the resistor is in phase with the voltage, while the current in the inductor is a quarter-cycle (90 degrees) behind. Supposing they both draw 1 amp on a 12-volt AC supply. The resistor will dissipate 12 watts, while the inductor will dissipate no power. Any power that enters the inductor comes back to the generator in a later part of the cycle. But the current drawn from the supply is 1.414 amps, so this would be a load with a power factor of 0.707.
If there's nothing else between the ends of the resistor and the power supply, then the voltage across the resistor is 24 volts, and the current through it is 2 amperes.
66W 230/800= 0,2875. 230= 66w
In an electronic circuit power supply voltage is generally fixed. Resistors is a current limiter for correct devices polarization.
A cement resistor is typically used as a power resistor (a resistor whose power rating is greater than 1 W).