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You just stated that the voltage across the resistor is 15 volts, so that's your answer !

If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts.

The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.

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14y ago
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Q: Voltage drop of 15 Volts across 2.7 killo ohm resistor?
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