If there's nothing else between the ends of the resistor and the power supply, then
the voltage across the resistor is 24 volts, and the current through it is 2 amperes.
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
A 10 ohm resistor across a 20 volt source has 2 amps flowing through it. A 20 volt source providing 2 amps is producing 40 watts. Voltage is Resistance times AmperesWatts is Voltage times AmperesAlternative AnswerDivide the square of the voltage by the resistance.
To tell you that we need to know the resistance of the entire circuit.
What is the voltage drop running through resistor one
Start with the load of 0.2 watts. The power rule says that watts equals volts times amps, or amps equals watts divided by volts, so 0.2 watts at 120 volts means 0.00167 amps. Now, look at Kirchoff's current law, which implies that the current in a series circuit is the same at all points. This means that the current in the resistor is also 0.00167 amps. Now, look at Kirchoff's voltage law, which implies that the sum of the voltage drops in a series circuit adds up to the voltage source. This means that the voltage across the resistor is 157 volts. Last, look at Ohm's law, which says that resistance is voltage divided by current. 157 volts divided by 0.00167 amps is 94,200 ohms. The nearest standard 5% value to that is 91,000 Ohms. Before leaving, though, check the power in the resistor. It is 157 volts times 0.00167 amps, or 0.26 watts, so you need at least a half watt resistor.
If there is nothing else in the circuit, then the voltage drop across the resistor will be the full supply voltage of 5 volts. The size of the resistor does not matter in this case - it will always be 5 volts.
The question is a bit ambiguous, but I will try to address it. If the 6 ohm resistance is in series with another resistance then some of the 5 volts would be dropped across the 6 ohm resistance and the remainder of the voltage would be dropped across the other resistance. To calculate the voltage, use the 'resistor voltage divider equation' (Google it). If the 5 volts is applied across only a 6 ohm resistance, then the top of the resistor is at 5 volts and the bottom of the resistor would be at 0 volts. The resistor would drop all of the voltage.
The question is incomplete without the voltage across the resistor. For example: if V (Voltage across 500 ohm resistor) = 5 Volts, then, Current, I = 5/500 Ampere = 0.01 A.
You just stated that the voltage across the resistor is 15 volts, so that's your answer ! If the resistor is connected to a 15-V battery or to the output of a 15-V power supply, then a meter across the resistor is also across the power supply, and reads 15 volts. The current through the resistor is (V/R) = (15/2700) = 5.56 mA. The power dissipated by the resistor (and delivered by the battery) is (V2/R) = (225/2700) = 0.083 watt.
The related link describes a 100 volt source driving three unknown resistors in series, with a fourth resistor of 10 ohms in parallel with one of the three resistors. It is stated that the voltage across the 10 ohm resistor is 20 volts. By Ohm's Law, current is voltage divided by resistance, so the current through the 10 ohm resistor is 2 amperes. Since you were provided with the voltage across the 10 ohm resistor, it does not matter what the value of the other three resistors is. However, and this is important to note... The voltage source and three resistors are not shown with any kind of connection to ground, so the circuit, as drawn, is invalid. Nevertheless, the voltage stated across the 10 ohm resistor was 20 volts, so there must be some kind of connection, and that was the basis for the calculation above. If, on the other hand, the 20 volts is referenced to the voltage source, then the current from A to B is zero, because there is no circuit involving the 10 ohm resistor.
I don't see a question. Please clarify if you want an answer.
A 10 ohm resistor across a 20 volt source has 2 amps flowing through it. A 20 volt source providing 2 amps is producing 40 watts. Voltage is Resistance times AmperesWatts is Voltage times AmperesAlternative AnswerDivide the square of the voltage by the resistance.
Two Hundred
To tell you that we need to know the resistance of the entire circuit.
V = (I) x (R) = 2 x 12 = 24 volts
Voltage / Resistance = Current, you do the math
A resistor in parallel with a voltages source will not cause the voltage to drop, theoretically. To get a 20 volt drop you need a resistance in series, and the number of ohms is 20 divided by the current in amps. If the current is unknown or variable, the voltage can't be dropped by using a resistor.