Answer : increase
The time required to charge a capacitor to 63 percent (actually 63.2 percent) of full charge or to discharge it to 37 percent (actually 36.8 percent) of its initial voltage is known as the TIME CONSTANT (TC) of the circuit.
Figure 3-11. - RC time constant. The value of the time constant in seconds is equal to the product of the circuit resistance in ohms and the circuit capacitance in farads. The value of one time constant is expressed mathematically as t = RC.
First, this statement stands as long as voltage is constant. If you held the current constant then power would increase as resistance increases.V=IR. For a fixed voltage if you increase the resistance (R) then the current (I) will decrease - following the formula.Power = VI so as the resistance increases the value of VI (power) decreases as V is constant and I gets smaller.Therefore the power is decreasing as the resistance increases (when voltage is held constant).Hope this helps.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
The value of resistance when there is a short circuit varies depending on the nature of the fault, but it could be fractionally above zero or higher.
1.cosine 2.exponential 3.min-max value 4.sine
If the resistance is increased the current, which is inversely proportional, decreases and, the voltage drop increases.
increases. Time constant, denoted by τ, is equal to the product of resistance (R) and capacitance (C), τ = RC. If the resistance increases, it will take longer for the capacitor to charge or discharge, resulting in a longer time constant.
First, this statement stands as long as voltage is constant. If you held the current constant then power would increase as resistance increases.V=IR. For a fixed voltage if you increase the resistance (R) then the current (I) will decrease - following the formula.Power = VI so as the resistance increases the value of VI (power) decreases as V is constant and I gets smaller.Therefore the power is decreasing as the resistance increases (when voltage is held constant).Hope this helps.
Yes, if the resistance remains constant. Power is voltage times current, and current is voltage divided by resistance, so power is voltage squared divided by resistance. In essence, the power increases as the square of the voltage.
U didn't clearify resistance in what aspect. If u mean electrical resistance,Resistance is phenomenum which describes the limitation of the flow of electric current in an electrical circuit. According to Ohms law (V=IR),the value of resistance is directly proportional to the value of voltage and inversely proportional to the value of current.That is,as the value of resustance increased,voltage also increases;also if the valur of resistance increases,the current reduces(as in I=V/R)
A variable resistor is a component that can change its resistance value. By adjusting the resistance, it can control the flow of electric current in a circuit. Increasing the resistance reduces the current flow, while decreasing the resistance increases the current flow. This allows for precise control of the current in a circuit.
An arithmetic sequence is a numerical pattern where each term increases or decreases by a constant value. This constant value is called the common difference.
ohms
The value of resistance when there is a short circuit varies depending on the nature of the fault, but it could be fractionally above zero or higher.
1.cosine 2.exponential 3.min-max value 4.sine
Resistance in a circuit is its ohmic value of the circuit. It is comprised of all of the devices and components that make up the circuit. This also includes the wire that carries the voltage to the load of the circuit.
The inductive time constant (L/R) is calculated by dividing the inductance of the inductor (L) by the resistance of the circuit (R). It represents the time it takes for the current in the circuit to reach approximately 63.2% of its maximum value during the charging or discharging of the inductor.
Generally the voltage is constant and current varies as per the load. Load can vary and hence current can vary. You are stating an abnormal situation, where in voltage increases while current remains constant. I am assuming a constant load situation then normally when voltage increases, the current tends to reduce since over all load remains same. If the voltage goes up beyond a limit the insulation fails and may lead to short circuit, equipment failure, shock and fatality