what is the other name of common emitter amplifier
GAIN is a function of load current but basically a small current in the base will make a big change of collector current therefore making a transistor a voltage amplifier as opposed to a current amplifier
180 degree phase shift
A: As current begins to flow the action on a resistance will be a voltage drop which is inversely proportional to the current. Making it a voltage amplifier as opposed to a tube where it is a current amplifier
An amplifier makes a (generally larger) copy of a signal or voltage. A rectifier allows current to pass in only one direction.
I think you mean a common emitter amplifier, which is an amplifier of voltage. Emitter-follower or common collector amplifiers are used to match impedances, or to amplify power or current. The emitter-follower is a type of common emitter circuit that has a resistor between the emitter and ground. The output signal is taken from the point between the emitter and its resistor.
A: REFERS TO A common emitter amplifier
bias
Gain of ce-cb cascode is nearly equal to the gain of ce amplifier, because in a ce-cb cascode, the gain of the ce stage is equal to 1, and the gain of the cb stage is nearly equal to an isolated ce amplifier. Hence, gain of both are nearly equal. On the other hand, Bandwidth of ce-cb cascode is much higher than the bandwidth of ce amplifier because the cb stage in the cascode configration is not subjected to any Miller effect, thereby improving the high frequency response. The absence of Miller effect is due to the fact that the base of the cb stage is grounded thus, shielding the collector signal from being fed back into the emitter input. To be more clear, the gain of CE stage in cascode is nearly 1, which reduces the miller effect on the cb stage greatly.
It should be ~180 degrees out of phase, because a CE amplifier is an inverter. A BJT CE amplifier is a good example to look at. The output is across CE, and at a minimum total output voltage is split across CE and some resistor R. As a higher voltage is applied to the base, the current flow through CE increases as a result of the resistance of CE decreasing. This boils down to a simple voltage divider at the output, Vout = CE / (R + CE). As CE decreases as a result of the input increasing, Vout will decrease.
4.65
GAIN is a function of load current but basically a small current in the base will make a big change of collector current therefore making a transistor a voltage amplifier as opposed to a current amplifier
I dont no exact ans but am thinking this is the ans for that , we can take the o/p for the ce amplifier in two ways one across the collector resistor and other one ofter the coupling capacuitor with respect to the ground.
1.CE amplifier circuit 2.LC oscillator circuit
180 degree phase shift
Cece Jones.
1)in cc configuration we use to get the low output impedence where as in ce we use to get the high output impedence. 2)in cc amplifier we use to have the voltage gain equal to unity where as in ce amplifier we use to have the high voltage gain. 3)in cc amplifier there is high power gai which is used for impedence matching where as in ce amplifier due to the high voltage gain the impedence matching is less impossible.
The signal gain of a CE BJT amplifier is hFe or collector resistance divided by emitter resistance, whichever is less.