frequency drops
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
If you're talking about an electric motor, increasing the frequency will increase the speed of rotation of the motor, and decreasing the frequency will decrease the speed of rotation of the motor. The other way of controlling a motor is to control the current; increasing the current increases speed, decreasing current decreases speed.
You use a capacitor to store electrostatic energy. You use an inductor to store electromagnetic energy. You use a resistor to dissipate electrical energy.
If the resistance is in series with the capacitor, the charge/discharge time is extended.
Oversizing the capacitor can shorten motor life.
There is no effect on frequency but the amplitude is increased
for inductor, reactance XL = 2*pi* f *L, if frequency doubles then reactance increase. But for capacitor, reactance Xc = 1/(2*pi*f*C). In this case if frequency doubles the reactance decrease.
Increasing the wavelength results in decreasing the frequency and decreasing the energy.
The emitter bypass capacitor, in a typical common emitter configuration, increases gain as a function of frequency, making a high pass filter. Removing the capacitor will remove the gain component due to frequency, and the amplifier will degrade to its DC characteristics.
the spring stiffness effect the natural frequency of the beam. the increasing value of spring stiffness lead to the increase value of natural frequency of the beam also.
Decreases axial r
The capacitor on it's own is of no use, it is always used in an RC or LC configuration normally in audio frequency's the RC is used to filter the noise down to earth where the RC circuit have to resonate at the same frequency as the noise, the lower the frequency the larger the value of the capacitor
The differential equation for a capacitor is dv/dt = i/c. Set that up in a circuit and force an AC power source, such as sin(theta), and you will see that lowering the frequency will increase the equivalent resistance. I'll leave that exercise for you. The net result is that a series capacitor is a high-pass filter, while a parallel capacitor is a low-pass filter.
Gain in a CE configuration of a BJT is collector resistance divided by emitter resistance, subject to the limit of hFe. The emitter bypass capacitor will have lower impedance at high frequency, so the gain will be higher at higher frequency, making this a high-pass amplifier.
the circuit will pass waves of a lower frequency
A: A TRANSISTOR gain is determined by current flow on the collector by adding a resistor to the emitter this current flow is reduced by adding or bypassing this resistor with a capacitor the net effect is that this emitter resistor will be reduced in value as frequency increases therefore change gain as a function of frequency input
Yes. If the sample is a random drawing from the population, then as the size increases, the relative frequency of each interval from the sample should be a better estimate of the relative frequency in the population. Now, in practical terms, increasing a small sample will have a larger effect than increasing a large sample. For example, increasing a sample from 10 to 100 will have a larger effect than increasing a sample from 1000 to 10,000. The one exception to this, that I can think of, is if the focus of the study is on a very rare occurrence.