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What happens when an inductive coil is first connected across a dc supply?
Davikat
Inductors tend to oppose a change in current, so the initial current is low, and rises according to the RC time constant of the circuit to a final value.
Wiki User
∙ 15y ago
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How is the power factor meter connected?
power factor meters are connected across the supply
Why at resonance the voltage drop across inductance and the voltage drop across capacitance is greater than the source voltage?
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
What does a inductor do when connected across ac supply?
opposes changes in current
What is purpose of diode in solenoid?
If the coil is powered with DC voltage, an inductive voltage is created anytime power to the coil is de-energized. The inductive voltage is called an inductive kick and it is up to ten times the applied voltage and is in reverse polarity to the applied voltage. A diode or other type of suppression device must be connected across the coil of the solenoid to protect any other electronic components in the circuit that may be damaged by this voltage. The diode is connected in reverse bias across the DC solenoid coil so that when voltage is applied in normal polarity, the diode does not provide a path for current. When the solenoid coil is de-energized, the inductive voltage is the opposite polarity to the power supply, so it will flow through the diode and back into the coil. Since the coil is made of a large length of wire. the energy of the inductive voltage will be dissipated as it moves through the wire. This will render the excessive inductive voltage harmless. The fact that the inductive voltage will travel through the diode in the forward bias direction means the 0.7-1 volt drop across the diode junction will also limit the V=< (dv/dt) surge. Fig. 4 (below) illustrates an example of the diode connected across the coil of a solenoid that is powered with DC voltage.
Why capacitor bank not connected across Diesel generator power supply?
I dont know.... may be due to save money
How do you connect an ammeter and voltmeter?
The voltmeter is connected across the supply and the ammeter is connected in series with the supply.
How is the power factor meter connected?
power factor meters are connected across the supply
What is the effect on the supply current if the capacitor removed?
It depends on how the capacitor is connected and whether the supply voltage is a.c. or d.c. Assuming you are talking about a power-factor improvement capacitor (connected in parallel with an inductive load, supplied with a.c.), then the supply current will reduce.
When a series circuit containing resistance and inductive reactance is connected to a ac supply the current will?
The load current will lag the supply voltage by an angle called a 'phase angle', determined by the values of resistance and inductive reactance. The magnitude of the load current will be determined by the impedance of the circuit, which is the vector sum of the resistance and inductive reactance.
Why at resonance the voltage drop across inductance and the voltage drop across capacitance is greater than the source voltage?
This isn't necessarily the case. It depends upon the value of resistance (which, at resonance, determines the current), and the values of the inductive- and capacitive-reactance.At resonance, the impedance of the circuit is equal to its resistance. This is because the vector sum of resistance, inductive reactance, and capacitive reactance, is equal the the resistance. This happens because, at resonance, the inductive- and capacitive-reactance are equal but opposite. Although they still actually exist, individually.If the resistance is low in comparison to the inductive and capacitive reactance, then the large current will cause a large voltage drop across the inductive reactance and a large voltage drop across the capacitive reactance. Because these two voltage drops are equal, but act the opposite sense to each other, the net reactive voltage drop is zero.So, at (series) resonance:a. the circuit's impedance is its resistance (Z = R)b. the current is maximumc. the voltage drop across the resistive component is equal to the supply voltaged. the voltage drop across the inductive-reactance component is the product of the supply current and the inductive reactancee. the voltage drop across the capacitive-reactance component is the product of the supply current and the capacitive reactancef. the voltage drop across both inductive- and capacitive-reactance is zero.
What does a inductor do when connected across ac supply?
opposes changes in current
What happens to supply voltage if additional resistance is connected in parallel circuit?
No change in supply voltage as additional resistance is connected in parallel circuit.
What happens if a DC motor is connected to an AC supply?
Through loda
What is the amount of power consumed by a 60 watt 220 volt lamp when it is connected across 110 volt supply?
What is the amount of power consumed by a 60 watt 220 volt lamp when it is connected across 110 volt supply?
What is purpose of diode in solenoid?
If the coil is powered with DC voltage, an inductive voltage is created anytime power to the coil is de-energized. The inductive voltage is called an inductive kick and it is up to ten times the applied voltage and is in reverse polarity to the applied voltage. A diode or other type of suppression device must be connected across the coil of the solenoid to protect any other electronic components in the circuit that may be damaged by this voltage. The diode is connected in reverse bias across the DC solenoid coil so that when voltage is applied in normal polarity, the diode does not provide a path for current. When the solenoid coil is de-energized, the inductive voltage is the opposite polarity to the power supply, so it will flow through the diode and back into the coil. Since the coil is made of a large length of wire. the energy of the inductive voltage will be dissipated as it moves through the wire. This will render the excessive inductive voltage harmless. The fact that the inductive voltage will travel through the diode in the forward bias direction means the 0.7-1 volt drop across the diode junction will also limit the V=< (dv/dt) surge. Fig. 4 (below) illustrates an example of the diode connected across the coil of a solenoid that is powered with DC voltage.
What happens to a voltage as the Christmas lights are connected in series?
Divide the number of lamps into the value of the supply voltage, and that will tell you the voltage drop appearing across each lamp. Bear in mind that if one of the lamps should be removed, the full supply voltage will then appear across the empty lamp holder.
What is the effect of an inductive or capacitive load under no load conditions?
A load of any type,,,inductive or capacitive , would effect the circuit even if THOSE "loads" had no load on them. They would still have a load effect on the circuit they are connected to.Answer'Under no-load conditions' means that no load is connected to the supply. So your question doesn't make sense!
