V=i*r 18-15=3*r r=3/3=1 ohm
The input to the max232 ic will be of Transistor Transistor Logic (TTL) and its voltage range will be of 5 volt. The output of the max 232 ic will be of Recomended Standard 232 Logic (RS232 logic) and its voltage range will be of 12 volt. The max 232 ic which is operating on 5 volt supply has to step up the 5 volt input to 12 volt. Hence a capacitor is used for pumping the voltage and called as pumping capacitor.
This question can be answered using voltage dividers. Assume the power supply consists of a voltage source and a resistor. With no load, all of the voltage source's voltage is dissipated by the internal resistor of 15V. When there is a load, there are two resistors in series. To calculate the internal resistance:1. I=V/R. You know the 600ohm resistor dissipated 13.7V. So that would mean a current of 13.7/600=22.8mA2. If the 600ohm resistor dropped 13.7, kirchoff's voltage law would tell us the internal resistor dropped 15-13.7=1.3V.3. R=V/I, Use the current to calculate the internal resistance. 1.3/22.8mA = 56.9ohmsCommentFurther to the above answer, a voltage-source's voltage is not 'dissipated by the internal resistance when on no load'. On no load, there is no current passing through the internal resistance, so no 'voltage dissipation' can takes plac -i.e. the non-load voltage is 15 V.
15v appliances
-7
it regulates +15v constant at output.
Yes you can. It will just take a little longer to complete the charge cycle.
somehow
11-15v from batt.
Almost certainly.
15(u + v - 2)
, No. I did it powering a 15V peavey audio mixer using a lead acid 12V battery. But depending of your audio mixer, you may have levels problems. Emmanuel
A: Disregarding the fact of different voltages there is the power to be concerned 9v x 1A = 9W, 15V X .8 = 12W. THE DEVICE WILL BE UNDER POWER.
It's a power supply with a positive and negative voltage, where one of the voltages tracks the other. For example: the negative voltage tracks the positive. If you regulate the positive to 15v, the negative is going to be -15v. This allows very precise symmetric power.
It will glow VERY BRIGHTLY for a few seconds - and then burn out.