Off hook must be at least a 20 mA draw. The upper end is usually determined by line resistance from the CO to the phone. The normal range seems to be 25-45 mA.
On hook voltage is a nominal 48V. However if you understand batteries, (in your car the battery is spec'd as 12 V but 14 V is usually what you get) 48 V is the low end and you can get as much as 56 V but due to various factors 53 V seems to be the usual normal. Off hook voltage is determined by line resistance and the actual phone. Normally 6-9 V is what you will see at the phone.
fet is a voltage controlled device...cut off voltage in fet refers to that voltage of the gate - source junction at which the current flow through channel is zero
Cutoff voltage is the point at which the battery is fully discharged. This is usually the point at which the device will shut itself off.
Pinch off voltage is defined as the gate-to-source voltage at which drain-to-source current is zero.Proof:-(In the saturation region)IDS = IDSS [1- (VGS/VP)]2When IDS = O ,VGS = VP
Voltage is equal to the Current multiplied by the Resistance.Without changing the resistance, increasing the applied voltage in a circuit will increase current flow. There is a simple, direct relationship between voltage and current. Double the voltage, twice the current will flow. Triple the voltage, and the current will triple. As voltage (E) equals current (I) times resistance (R), when resistance is fixed, what happens to voltage will happen to current.
answer is actually voltage
it has 52volt dc off hook
Basically it takes a higher current to start a fluorescent lamp that it does to sustain the arc. (It's higher current, not voltage. The voltage is constant.) The ballast regulates the current flow through the lamp. Removing the voltage from devices requiring power will turn any device off.
fet is a voltage controlled device...cut off voltage in fet refers to that voltage of the gate - source junction at which the current flow through channel is zero
fet is a voltage controlled device...cut off voltage in fet refers to that voltage of the gate - source junction at which the current flow through channel is zero
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
Voltage = (current) x (resistance) Current = (voltage)/(resistance) Resistance = (voltage)/(current)
it depends on what type of load. Motor amperage will drop off as voltage rises. loads such as lights will increase amperage with voltage rise.
NO! where does the power (voltage and current) come from if the battery is flat/dead?
According to ohm's law, voltage in a circuit is directly proportional to current in the circuit and when that proportionality sign is taken off to equals to, a constant is introduced with current and is called resistance. Therefore Voltage in a circuit equals to product of current and resistance in that circuit.
Pinch-off voltage in a Field Effect Transistor (FET) refers to the specific gate-to-source voltage at which the channel conducting current begins to 'pinch off' or constrict. Beyond this voltage, increasing the gate voltage does not significantly increase the drain current; instead, the current becomes relatively constant as the channel narrows and limits the flow of charge carriers. This phenomenon is crucial for the operation of FETs in saturation mode, where the device is used for amplification and switching applications.
Cutoff voltage is the point at which the battery is fully discharged. This is usually the point at which the device will shut itself off.
In the graph of voltage vs current, the relationship between voltage and current is linear. This means that as voltage increases, current also increases proportionally.