The time constant of a 4.7 µF capacitor in series with a 22 KΩ resistor is about 103 ms.
The time constant of a 0.05 microfarad capacitor and a 200 K ohm resistor in series is simply their product, 0.05 times 200,000, or 10,000 microseconds, or 10 milliseconds. (Farads times ohms = seconds)
The time-constant is the resistance times the capacitance, so that's 47 x 47 and because the capacitance is in microfarads, the answer is in microseconds.
Equation for voltage across capacitor in series RC circuit is as follow, vc = V(1-e-t/RC) V = DC voltage source. So theoretically time taken for capacitor to charge up to V volt is INFINITY. But practically we assume 95% or 98% of source voltage as fully charge. RC is the time constant which is the time take for capacitor to charge 63%. In this case time constant is 500uF*2.7Kohm = 1.3sec Time taken to charge 95% = 3*T = 3*1.3 = 3.9sec T = time constant Time taken to charge 98% = 4*T = 4*1.3 = 5.2sec
This capacitor carries a current of 25,000/690 or 36.2 amps and its impedance (reactance) is 19 ohms. The capacitance is 1/(2.pi.50.19) or 0.000167 Farad, on a 50 Hz system. The time-constant is CR so that if a 20,000 ohm resistor is placed across the capacitor the time-constant is 3.3 seconds. The voltage is reduced by 99% after 5 time-constants or in this case 17 seconds. If the discharge resistor is permanently in circuit it dissipates 690^2 / 20000 or 24 watts.
A resistor is used to limit current flow through a capacitor.If you did not use the resistor, you could potentially create large currents through the capacitor, damaging it. Capacitors do have current limit ratings - check the specification sheet for the capacitor.Also, in the case of an electrolytic capacitor, if it is generally in a discharged state then it is necessary from time to time to reform it. That process involved slowly charging it, i.e. through a resistor, and then letting it discharge by itself with no or little load. The resistor protects both the capacitor and the voltage source in the case that the capacitor might be shorted.
The same as the time constant of a 2.7 microfarad capacitor and a 33 ohm resistor connected in series.
In theory ... on paper where you have ideal components ... a capacitor all by itself doesn't have a time constant. It charges instantly. It only charges exponentially according to a time constant when it's in series with a resistor, and the time constant is (RC). Keeping the same capacitor, you change the time constant by changing the value of the resistor.
A: It is called discharging a capacitor. The charge will follow the rules of a time constant set up by the series resistor and the capacitor. 1 time constant 63% of the charge will be reached and continue at that rate.
The time constant of a 0.05 microfarad capacitor and a 200 K ohm resistor in series is simply their product, 0.05 times 200,000, or 10,000 microseconds, or 10 milliseconds. (Farads times ohms = seconds)
the capacitor and its associated resistor set the time constant.
Usually a tiny fraction of a second. Actually it will depend on the characteristics of the the capacitor, and of the remaining circuit (mainly, any resistor in series). The "time constant" of a capacitor with a resistor in series to charge from 0 to a fraction of (1 - 1/e), about 68%, of its final value. This time is the product of the resistance and the capacitance. After about 5 time constant, you can consider the capacitor completely loaded for all practical purposes - i.e., it will be at the same voltage as the battery.
A resistor by itself has no time constant. For a circuit to have a time constant it must contain either capacitors or inductors.
RL circuit consists of a resistor and an inductor connected in series, while an RC circuit consists of a resistor and a capacitor connected in series. In an RL circuit, the time constant is determined by the resistance and inductance, while in an RC circuit, the time constant is determined by the resistance and capacitance. RL circuits respond to changes in current, while RC circuits respond to changes in voltage.
Because the timing is set by the time constant of a resistor and a capacitor. With R in ohms and C in Farads, the time-constant is RC in seconds. If the capacitor leaks the timing will be wrong.
A: Mathematically speaking the capacitor will never charge to the source because it takes one time constant to reach 63% and so on but for practical uses it is assume to be fully charged in 5 time constants R X C = 1 TIME CONSTANT
2*103*10-5 = 2*10-2 Seconds = 20 milliseconds
Capacitors don't have time constants. The combination of a capacitor and aresistor has a time constant. It's equal to the product of the resistance (ohms)and the capacitance (farads), and has the units of time.When the capacitor is allowed to discharge through the resistor, the voltage onthe capacitor and the current through the resistor both decrease steadily as thecapacitor empties. The time constant is the time it takes for those quantities todecrease to 36.8% (1/e) of what they were one time-constant earlier.4,700F is an enormous capacitor. But OK, if that's its real value, then in order tohave a time constant of 12 seconds, we can calculate the resistance like this:RC = 12 secondsR = 12/C = 12/4,700 = 0.00255 ohm.Now we ( I ) understand what the question is talking about !0.00255 ohm is not an external resistor connected in series with the capacitor.It must be the effective internal resistance of the capacitor itself. The performancespec of 12 seconds for the device is telling you that it has a very low internalresistance, so you can get current (energy) in and out of it fast. As a circuit-design component, it blurs the distinction between a capacitor and a battery.