The time-constant is the resistance times the capacitance, so that's 47 x 47 and because the capacitance is in microfarads, the answer is in microseconds.
The time constant of a 0.05 microfarad capacitor and a 200 K ohm resistor in series is simply their product, 0.05 times 200,000, or 10,000 microseconds, or 10 milliseconds. (Farads times ohms = seconds)
The time constant of a 4.7 µF capacitor in series with a 22 KΩ resistor is about 103 ms.
In an RC network,the Time Constant τ (tau) is calculated as shown below. τ = RC For a 10 kOhm and 100 microFarad RC network: τ = 10000 x 100x10-6 τ = 1 second
This capacitor carries a current of 25,000/690 or 36.2 amps and its impedance (reactance) is 19 ohms. The capacitance is 1/(2.pi.50.19) or 0.000167 Farad, on a 50 Hz system. The time-constant is CR so that if a 20,000 ohm resistor is placed across the capacitor the time-constant is 3.3 seconds. The voltage is reduced by 99% after 5 time-constants or in this case 17 seconds. If the discharge resistor is permanently in circuit it dissipates 690^2 / 20000 or 24 watts.
The time constant is equivalent to 1/(R*C); since C (the capacitance of the capacitor) is not changing, yes, the charging and discharging times will be the same, provided the Thevenin resistance is the same as well - if you charge a capacitor using a AA battery, then remove the battery, and discharge through a resistor, you have changed the Thevenin resistance, thus the discharge time will NOT be equal.
The same as the time constant of a 2.7 microfarad capacitor and a 33 ohm resistor connected in series.
The time constant of a 0.05 microfarad capacitor and a 200 K ohm resistor in series is simply their product, 0.05 times 200,000, or 10,000 microseconds, or 10 milliseconds. (Farads times ohms = seconds)
If a 10 microfarad capacitor is charged through a 10 ohm resistor, it will theoretically never reach full charge. Practically, however, it can be considered fully charged after 5 time constants. One time constant is farads times ohms, so the time constant for a 10 microfarad capacitor and a 10 ohm resistor is 100 microseconds. Full charge will be about 500 microseconds.
2*103*10-5 = 2*10-2 Seconds = 20 milliseconds
the capacitor and its associated resistor set the time constant.
The time constant of a 4.7 µF capacitor in series with a 22 KΩ resistor is about 103 ms.
In theory ... on paper where you have ideal components ... a capacitor all by itself doesn't have a time constant. It charges instantly. It only charges exponentially according to a time constant when it's in series with a resistor, and the time constant is (RC). Keeping the same capacitor, you change the time constant by changing the value of the resistor.
Because the timing is set by the time constant of a resistor and a capacitor. With R in ohms and C in Farads, the time-constant is RC in seconds. If the capacitor leaks the timing will be wrong.
A: It is called discharging a capacitor. The charge will follow the rules of a time constant set up by the series resistor and the capacitor. 1 time constant 63% of the charge will be reached and continue at that rate.
Time constant = capacitance x resistance --> farads x ohms simplifies to units of seconds. (2 x 10-6 farads) x (2 x 103 ohms) = 4 x 10-3 seconds
No, the value is far too small. If it is the capacitor used for the timing, the time/s will be reduced to one tenth of the deisred value.
Usually a tiny fraction of a second. Actually it will depend on the characteristics of the the capacitor, and of the remaining circuit (mainly, any resistor in series). The "time constant" of a capacitor with a resistor in series to charge from 0 to a fraction of (1 - 1/e), about 68%, of its final value. This time is the product of the resistance and the capacitance. After about 5 time constant, you can consider the capacitor completely loaded for all practical purposes - i.e., it will be at the same voltage as the battery.