No, the value is far too small. If it is the capacitor used for the timing, the time/s will be reduced to one tenth of the deisred value.
The unit of capacitor is farad. 1 farad =10 to the power of 6 microfarad and also = 10 to the power of 12 picofarad Therfore if you are replacing one picofarad capcitor into one microfarad capacitor you are increasing the capcitance to 1000000 times. If it is in an oscillator circuit you are changing the frequency drastically which will be of no use.
The same as the time constant of a 2.7 microfarad capacitor and a 33 ohm resistor connected in series.
tuned circuit consists of resistance and capacitor so this one RC circuit formula to be used f = 1/ 2 pi RC
The capacitive reactance is approximately 4 kΩ .
A 10k c1 typically refers to a 10,000 ohm capacitor with a capacitance rating of 1 microfarad. The value of this capacitor indicates its ability to store and release electrical charge in a circuit.
No! This is a term for capacitance. A capacitor will store a voltage up to it's breakdown limit plus cause a voltage reaction to a following circuit.
The capacitor symbol looks like: --|(--
The difference between a 5 microfarad (UF) and a 15 microfarad capacitor lies in their capacitance values, which indicate their ability to store electrical charge. A 15 UF capacitor can store three times more charge than a 5 UF capacitor at the same voltage. This larger capacitance makes the 15 UF capacitor more suitable for applications requiring higher energy storage or filtering capabilities. Additionally, the choice between them will depend on the specific requirements of the circuit where they are used.
2*103*10-5 = 2*10-2 Seconds = 20 milliseconds
Yes, you can use a capacitor with a higher microfarad (µF) rating, but it's important to ensure that the voltage rating is appropriate for your circuit. A higher capacitance will increase the capacitance value, which can affect the circuit's performance, such as smoothing out voltage fluctuations or changing the timing characteristics in timing circuits. However, make sure the circuit can handle the increased capacitance without issues like excessive current draw or slower response times.
Not a good idea, without knowing more about the circuit in which it's installed. Presumably, the 440v capacitor was selected because its max voltage rating (440v) is higher than the instantaneous voltage to be expected at that point in the circuit. By that criterion, the voltage at that point in the circuit may exceed 370 volts, and your proposed replacement component won't hold it.
A small capacitor can be part of an integrated circuit.