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You describe a series circuit. This answer is for a series circuit. The total impedance is 16 Ohms, 12 + 4. The current by Ohm's Law (Amps = Volts / Ohms) is 40 / 16, or 2.5 Amps. Kirchoff's Current Law says that the current at every point in a series circuit is the same, so the current flowing into the 1st device, the 12 Ohm resistor, is 2.5 Amps.

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14y ago
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15y ago

Ohm's law is V = I * R.

The current I = V / R = 40 volts divided by 4 ohms = 10 amps.

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15y ago

in series: 2.5A.

I = E/R (Ohm's Law)

I = 40v / (12+4 = 16)

I = 40/16

I = 2.5.

http://www.play-hookey.com/dc_theory/ohms_law.html

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Q: What is the current flowing through the first device of a circuit when the first device has a resistance of 12 ohms and the 2nd device has a resistance of 4 ohms circuit voltage is 40 volts.?
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