not affected in powerfactor then u easily specified in MVA
By definition, MVA is equivalent to the vector sum of MW and MVAR: MVA^2 = MW^2 + MVAR^2 = 2500 MVA = 50
You would have to know the Power Factor, normally designated PF. MVA x PF = MW. If the PF is unity then MVA = MW. A PF of UNITY suggest the load is purely resistive with neither capacitive nor inductive components in the load or source. Of course this can mean such components have been balanced artificially.
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
500 MW Boiler is sub-critical Boiler which generates steam at pressure lower than the critical pressure ie below 221.2 kg/sqcm. where as the 660 MW boiler is super critical boiler which operates steam pressure above critical pressure.
1 kw = 0.001 mw 25 kw = 0.025 mw
There are two concerns here regarding loading on transformers of this size. First is the difference between MVA and MW. MW is just real power -- watts. MVA is total power which includes real power (MW) and reactive power (MVAR).--- http://en.allexperts.com/q/Electric-Power-Utilities-2405/operation-limit-oof-power.htm
MVA is the apparent power. MVA=( MW+ MVAr)1/2
By definition, MVA is equivalent to the vector sum of MW and MVAR: MVA^2 = MW^2 + MVAR^2 = 2500 MVA = 50
You would have to know the Power Factor, normally designated PF. MVA x PF = MW. If the PF is unity then MVA = MW. A PF of UNITY suggest the load is purely resistive with neither capacitive nor inductive components in the load or source. Of course this can mean such components have been balanced artificially.
MVA= square root of (MW2 + MVAR2 )
Large transformers are filled with oil which circulates to a radiator to get rid of excess heat. A 100 MVA transformer should waste about 1 MW of power on full load, 0.5 MW on no load.
mw/mva=power factor reactive power(Q)=I2XL or E2/XL where XL= REACTANCE apparent power = square root of (MW2 + MVAR2 )
You would have to know the Power Factor, normally designated PF. MVA x PF = MW. If the PF is unity then MVA = MW. A PF of UNITY suggest the load is purely resistive with neither capacitive nor inductive components in the load or source. Of course this can mean such components have been balanced artificially.
In a 1 megawatt (MW) generator, the unit of power is given in terms of megawatts, which represents one million watts. A megavolt-ampere (MVA) is a unit of apparent power equal to one million volt-amperes. Therefore, in a 1 MW generator, the apparent power rating would also be 1 MVA, as the apparent power rating is typically equal to the real power rating in a generator with a power factor of 1.
Easy, you don't sell MVAh, you sell MWh. MVA is used in rating generators because it combines Watts and vars. MW is used to let you know what kind of money you can make, since you also are probably wanting to produce vars in order to support your grid.
The power in a 15 MVA (15000 KVA) transformer depends on the power factor. You did not specify the power factor, so I will assume a power factor of 0.92. Simply multiply MVA by PF and you get 13.8 MW.
A megawatt ('MW', not 'Mw') is used to measure power, which is the rate at which you use energy.A megawatt hour ('MW.h', not 'mwh') is used to measure energy, and is defined as 'the amount of energy consumed, per hour, at a rate of one megawatt'.