it reduces the gain
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR
The dc load resistance is Rc but the AC Load resistance is (RcRl). If a load line is drawn the slope of which is -1(Rc Rl) . Then it is called an AC load line and it is to be used when the transistor is operating as an amplifier.
This arrangement is called SELF-BIAS. Now, if an increase of temperature causes an increase in collector current, the collector voltage (VC) will fall because of the increase of voltage produced across the load resistor (RL). ... One of the most widely used combination-bias systems is the voltage-divider type
In a pure resistive circuit the voltage and current are in phase. In an inductive circuit they are fro zero to 180 degrees out of phase. If they are in phase the Power Factor is 1 and 180 degrees the PF is zero. The exact amount of the phase difference depends on the specific circuit.
The time constant of an RL series circuit is calculated using the formular: time constant=L/R
The effect of an RL circuit in half wave rectifier is that the voltage output wave forms for current and voltage will be modified .
An RL circuit is a circuit containing resistance (R) and an inductance (L).
Assuming galvanometer has zero or negligible internal resistance. If u connect resistor R>>RL(Load resistance) and connect it parallel to RL, it will hardly cause any change in voltage across load resistance. Suppose small current Ig goes through galvanometer. Since galvanometer have zero internal resistance, Voltage across RL = Voltage across R = IgR
Since the equation of an inductor is ... di/dt = v/L ... then increasing the current in the RL network would cause a back-emf in the inductor that would initially seem to oppose the series current. More correctly, the question should ask "what if the voltage were increased?"; and the answer is that the rate of change of current in the inductor would increase, but the current would not initially change. This is the case for a series RL. For a parallel RL, increasing the current would initially show up as an increase the the current through the R, increasing voltage in the L, with the same effect as noted above.
The dc load resistance is Rc but the AC Load resistance is (RcRl). If a load line is drawn the slope of which is -1(Rc Rl) . Then it is called an AC load line and it is to be used when the transistor is operating as an amplifier.
The values of Rs and Rl in a circuit impact the current and voltage levels within the circuit. Rs represents the source resistance affecting the input impedance, while Rl represents the load resistance affecting the output impedance. A variation in these values can cause changes in signal attenuation, power dissipation, and overall circuit performance.
RL stands for Road Luxery
Voltage drop across a circuit is IZ, where I is current and Z is impedance. In other words IZ = IR + jIX, where R is resistance and X is inductance
Use thevenin model for the output of the power supply. That means there is a voltage source Vs, output resistance Rs and the series load RL which is a short with a resistance value equal to zero ohms. So, voltage across it is zero. The full voltage drops across the resistance Rs according to KVL.
The current flowing through the load terminals Rl connected across any two terminals A & B of a linear, bilateral, active network is given by Voc/Rth + RL where VOC is the open circuit voltage across the terminals A & B & RL is the internal resistance of the network as viewed back into the open circuited network from AB deactivating all the independent sources.
RL sine had no Sisters
rl-eligibility