R = resistance = rho * L / S
rho is resisitivity in [Ohm m], it depends on the material (Copper: 2e-8 [Ohm m])
L is wire length [m]
S is wire cross section [m]
EDIT: for high frequencies, you may also wanto to take sink effect into account (~MHz)
There are various formula of load calculation. Power equals current multiplied by the voltage. Power can also be computed by multiplying the resistance by the square of the current.
resistance is directly proportional to wire length and inversely proportional to wire cross-sectional area. In other words, If the wire length is doubled, the resistance is doubled too. If the wire diameter is doubled, the resistance will reduce to 1/4 of the original resistance.
It shortens
Resistance is directly-proportional to the length and resistivity of a conductor, and inversely-proportional to its cross-sectional area. So a shorter wire would have less resistance than a longer wire made from the same material, and a wire with a greater cross-sectional area would have less resistance than one with a smaller cross-sectional area made from the same material. Resistivity depends on the material from which the wire is made, with some materials being better conductors than others. For example, silver has the lowest resistance compared with other metal conductors having identical dimensions. Similarly, a copper wire will have a lower resistance than an aluminium wire of identical dimensions.
5 ohms or less.
There are various formula of load calculation. Power equals current multiplied by the voltage. Power can also be computed by multiplying the resistance by the square of the current.
If the wire is short, its resistance will likely decrease. A shorter wire has less length for electrons to travel through, resulting in lower resistance according to the formula R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
The resistance of a wire is directly proportional to its length. This means that as the length of the wire increases, the resistance also increases. This relationship is described by the formula R = ρ * (L/A), where R is resistance, ρ is the resistivity of the material, L is the length of the wire, and A is its cross-sectional area.
The resistance of a wire is directly proportional to its length and inversely proportional to its cross-sectional area. This means that for a given material, a longer wire will have higher resistance and a thicker wire will have lower resistance. The relationship is described by the formula: Resistance = resistivity x (length / cross-sectional area).
Increasing the length of the wire will not reduce resistance in a copper wire. In fact, resistance is directly proportional to the length of the wire according to the formula R = ρ * (L/A), where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
The AC resistance of a 1000 kcmil aluminum wire over 500 ft will depend on the resistivity of aluminum, which is approximately 2.82 x 10^-8 ohm*m. The resistance can be calculated using the formula R = ρ * L / A, where ρ is the resistivity, L is the length, and A is the cross-sectional area of the wire. The presence of the steel conduit may affect the overall resistance, but specific information on the conduit material and dimensions would be needed for a more accurate calculation.
How do you calculate Resistance of 70mm2 single core wire?Read more: How_do_you_calculate_resistence_of_70mm2_single_core_wire
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Bends in a wire do not affect its resistance because the cross-sectional area and length of the wire remain the same regardless of the bends. Resistance is determined by these two factors, according to the formula R = ρ*(L/A), where ρ is the resistivity of the material, L is the length of the wire, and A is the cross-sectional area. As long as these parameters remain constant, the resistance of the wire will stay the same.
The unit of resistance is the Ohm, and by applying a small voltage to your wire, and measuring the resultant current, you may calculate the resistance.From the formula I = E/R, where R = resistance in Ohms, E is the voltage in volts, and I is the current in amperes.
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Electric resistance is greater in a longer, thinner wire compared to a shorter, fatter wire due to increased collisions between electrons and atoms in the longer wire, leading to higher resistance. This is described by the formula R = ρL/A, where R is resistance, ρ is resistivity of the material, L is length, and A is cross-sectional area.