The frequency of the power waveform in a capacitive circuit, or for that matter, an inductive circuit, is the same as the input voltage or current. Its just that the current leads the voltage (capacitor) or lags the voltage (inductor) by a phase angle, the cosine of which is the power factor.
It does not matter how many sine waves you have, or what their phase angle is; if they all have the same frequency, the resultant, by Fourier analysis, is still a sine wave of the same frequency.
VAr is reactive power, caused by either inductive or capacitive loads. The ideal power factor to have is 1, anything less than that is a loss on the network. The effect of VArs on the circuit though depends. If you have a load that is mainly inductive, then adding more inductive reactance will lower the power factor. However, if you introduce capacitive reactance this will increase the power factor, and the opposite is true if its a mainly capacitive circuit. So VArs will either increase or decrease the power factor depending on the load of the circuit. The ideal situation is to balance inductive reactance with capacitive reactance so they in effect cancel each other out and power factor is 1.
A capacitor is a device that resists a change in voltage, proportional to current and inversely proportional to capacitance. dv/dt = i/c An inductor is a device that resists a change in current, proportional to voltage and inversely proportional to inductance. di/dt = v/l In an AC circuit with capacitive loading, the current waveform will lead the voltage waveform; while with inductive loading, the current waveform will lag the voltage waveform.
No, as 100% efficiency is not possible.AnswerYes, it occurs at resonance. That is, when a circuit's inductive reactance is exactly equal to its capacitive reactance. This can be achieved by adjusting the frequency of the supply until resonance is achieved. Incidentally, power factor has nothing to do with 'efficiency'.
if the load is capacitance then reactive power is injected in the circuit, as we know that reactive power is directly proportional to the voltage, if there is increase in reactive power automatically voltage at load end of the tranformer is increases
That depends what circuit it is in. If it is in a sweep circuit (vertical/horizontal) no because it will change the frequency of the circuit. If it is in a power supply circuit, probably yes becuase it is probable only being used as a filter. BUT if that leg of the power circuit supplies a sweep circuit, no.
D.C power can be filtered using low pass capacitive circuit
The value of the half-power frequency in the circuit is the frequency at which the power is half of its maximum value.
VAr is reactive power, caused by either inductive or capacitive loads. The ideal power factor to have is 1, anything less than that is a loss on the network. The effect of VArs on the circuit though depends. If you have a load that is mainly inductive, then adding more inductive reactance will lower the power factor. However, if you introduce capacitive reactance this will increase the power factor, and the opposite is true if its a mainly capacitive circuit. So VArs will either increase or decrease the power factor depending on the load of the circuit. The ideal situation is to balance inductive reactance with capacitive reactance so they in effect cancel each other out and power factor is 1.
The different types of power factor are: # Leading ( Due to Capacitive Circuit) # Lagging (Due to Inductive Circuit) # Unity (Due to Resistive Circuit)
A capacitor is a device that resists a change in voltage, proportional to current and inversely proportional to capacitance. dv/dt = i/c An inductor is a device that resists a change in current, proportional to voltage and inversely proportional to inductance. di/dt = v/l In an AC circuit with capacitive loading, the current waveform will lead the voltage waveform; while with inductive loading, the current waveform will lag the voltage waveform.
In an L-C-R AC series circuit, resonance occurs when the capacitive and inductive reactances cancel each other out, resulting in minimum impedance. This causes the current in the circuit to be at its maximum and the power factor to be unity. By measuring the frequency at which resonance occurs, one can determine the values of the inductor, capacitor, and resistor in the circuit.
Frequency does not directly affect power. Power is determined by the voltage and current in a circuit, which are influenced by factors such as resistance and reactance. However, in some cases, changes in frequency can impact the impedance of a circuit, affecting the power consumption.
The cutoff frequency in an RL circuit is the frequency at which the output signal power is half of the maximum power. It is significant because it determines the range of frequencies that can pass through the circuit effectively, affecting the overall performance and functionality of the circuit.
A cycloconverter or a cycloinverter converts an AC waveform, such as the mains supply, to another AC waveform of a lower frequency, synthesizing the output waveform from segments of the AC supply without an intermediate direct-current link.
When there is an inductive element in the circuit, the current lags behind the voltage. an ideal inductor will make the current lag behind the voltage by 90 degrees..a capacitive element on the other hand will make the current lead the voltage (ideally by 90deg). That's why capacitors in parallel with the system are used a lot for power factor correction
XL=Xc is the resonance condition for an RLC circuit
The half power frequency is important in electrical engineering because it represents the point at which a circuit's power output is reduced by half. This frequency is used to determine the bandwidth of a circuit and is crucial for designing filters and amplifiers.