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Why is the capacitor used in tube light?
Starters in tube light uses capacitors to produce a momentary high voltage of 400V due to discharging of capacitor. This momentary high voltage will start the gaseous discharge to priduce light by initial flickering . now,if capacitor is not used , the power supply from the main cannot start the gaseous discharge .
Why inductor does not allow the sudden change of current?
an inductor has inductance(L). its unit is henry. when any change in currentin a inductor occurs it produces an self induced emf equal to e=-Ldi/dt volt. minus(-) sign indicates the direction of the induced voltage which is in opposition to the cause which is producing it. here the case is change in current(di/dt). that's why, whyan inductor opposes any change in voltage and hence current in it.
Why capacitor block direct current?
A capacitor opposes a change in voltage, but it will help to look at both the device and at a circuit up close to see what's going on. Any capacitor is two "plates" separated by a dielectric or insulator. Connect a wire to each plate and you've got the device. In a direct current circuit, the voltage source will cause current flow in only one direction. A common battery is a good example. Let's look further. When a capacitor is connected in a DC circuit and the circuit is energized, the voltage source will want to cause current to flow in only the one direction. In the initial moment when the power is switched on, electrons will flow in the circuit. Electrons will leave the negative terminal of the source and enter the positive terminal. The current flow will travel through the wire, and electrons will "pile up" on one of the plates of the capacitor. As electrons are "piling up" on one plate, their presence there will create an electric field across the dielectric to the other plate. This electric field will cause electrons on that other plate to leave. The capacitor is charging, and the voltage source will, for the first instant of time, think that things are "fine" and current will flow. But as the capacitor charges, current flow drops off, and it eventually stops when the voltage across the plates equals the source voltage. In review, as the DC power is switched on in a circuit with a capacitor in it, current will flow "normally" for the first instant. But as the first electrons arrive on one plate and force them off the other plate, current in the circuit will begin dropping off. The voltage developing across the plates of the capacitor opposes the battery voltage. Eventually the capacitor is charged and all current flow has stopped. There is some math that says something slightly different, but for all practical purposes, the capacitor is considered fully charged in a very short period of time. This will depend on circuit resistance and the ability of the source to deliver current, of course. But that capacitor will, when charged, not "pass" any more current. The voltage across the plates is equal to (an opposing) the source voltage, and no more electrons can get onto the negative plate to force more off the positive plate.
A baseball was thrown from 1 m hill Assume that the ball had an initial velocity of 70 kmh 19.44 ms at 40 degreesWhat was the initial velocity on x direction?
initial velocity on xx=vi*cos(angle) 53.62 kmh 14.89 ms
Time constant of an RC circuit increases if the value of the resistance is?
Answer : increase The time required to charge a capacitor to 63 percent (actually 63.2 percent) of full charge or to discharge it to 37 percent (actually 36.8 percent) of its initial voltage is known as the TIME CONSTANT (TC) of the circuit. Figure 3-11. - RC time constant. The value of the time constant in seconds is equal to the product of the circuit resistance in ohms and the circuit capacitance in farads. The value of one time constant is expressed mathematically as t = RC.
What are the initial conditions for voltage across the capacitor and current through the inductor in the dc steady state?
The initial condition is the voltage and/or current existing at the time a mathematical solution begins. Example: what happens when a resistor is connected across a capacitor? well, you say that at t=0 the resistor is connected, then after that the voltage across the capacitor is v0.exp(-t/RC), where v0 is the starting voltage, t is the time, R is the resistance and C is the capacitance. This simple solution needs only one initial condition which is the starting voltage v0 across the capacitor. Linear differential equations are common in electrical engineering and a complete solution of one (such as the example) always requires one or more initial conditions.
What is the differencebetween a run capacitor and start capacitor?
The run capacitor is used when the load is functional while the start capacitor is used to produce the initial torque to drive the load.
Suppose no energy given to inductor and a decreasing current is applied to it. emf will be produced and energy is given by it.so i think energy is not stored in inductor. it is its own property?
How do you propose to connect a decreasing current to the inductor ? The initial current through the inductor is zero, and you want to connect it to a current which is not zero and decreasing. At the instant you make the connection, the inductor current is zero, and it must rise to the non-zero value where you want it to begin decreasing. The current in the inductor cannot change from zero to something in zero time. As it rises from zero to the initial value, guess what . . . the inductor is storing energy in its magnetic field, while producing the usual voltage equal to [ L di/dt ].
Why initial current is always zero in an inductor and if it is due to 100 percent opposition then current should always remain zero because just after opposition current is zero than again?
When initially closing a switch into any electrical device, the initial condition will be zero current. I think you are getting confused about impulse response. An impulse (such as would result from closing a switch) is essentially a very short, high frequency wave. Inductors' impedance is equivalent to the wave frequency (in radians)*2*PI*inductance (in Henrys). You can see if the applied waveform is a very high frequency, the inductor's response will be to highly limit current flow. A capacitor's impedance is equivalent to 1/(frequency*2*Pi*capacitance); the impulse response of a capacitor is a very high current spike due to a very low impedance.
Is inductor linear or non linear when the initial in it is non zero taking output as current and input as voltage?
Linear
What happens when closing and breaking an inductive circuit?
When you close an inductive circuit, since an inductor resists a change in current, the initial reaction of the load is to look like a high resistance. As current builds, the resistance falls. With a theoretical source and inductor, current would eventually reach infinity, that is after infinite time, but practical sources and inductors will reach a plateau current. When you open an inductive circuit, again, since an inductor resists a change in current, the inductor attempts to maintain that current, but there is no conductivity for that current so, the inductor presents a high voltage spike in the reverse direction it was initially "charged" with. With a theoretical inductor, and theoretical infinite impedance, the voltage spike would be infinite. Again, practical inductors have a maximum voltage spike, but this spike can still be quite high, even thousands of volts, which can damage the circuit, so it is important to maintain a conduction path for the collapsing field, often a diode, or a resistor/capacitor filter.
What is a kit start for air conditioners?
a capacitor and relay that gives the compressor an initial boost and then cuts out of the system by way of the relay.
How a capacitor responds to step function initial and final condition?
Capacitors resist change in voltage, so initially it will want to keep it's voltage (across it) the same. Depending on the configuration, the cap could initially behave as a short to attempt maintain that condition, or as a voltage source (if voltage was already present across the cap, for instance).
What is the use of a 100 mfd capacitor in an arc welder?
A capacitor is a storage device like a battery it will however discharge at a rate of 63% for one RC time constant .so it is there to provide more initial force.
A capacitor is discharged through a 80 ohm resistor. The discharge current decreases to 29 percent of its initial value in 2 seconds. What is the value of the capacitor?
14 micro farads @ 1.4 seconds.. idk what it is at 2 seconds ;p
Why is the capacitor used in tube light?
Starters in tube light uses capacitors to produce a momentary high voltage of 400V due to discharging of capacitor. This momentary high voltage will start the gaseous discharge to priduce light by initial flickering . now,if capacitor is not used , the power supply from the main cannot start the gaseous discharge .
Is a higher capacitance better?
capacitor always opposes the change in voltage , at beginning it shows the initial value and after sum time it charges and shows the maximum valve . Higher capacitor has higher voltage after some time , therefore it damages the equipment.
