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Without knowing the circuit this cannot be determined. Sorry.

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Q: What is the peak forward current through each diode?
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Why diode use in parallel?

1. Redundancy: If one diode breaks (in a way that makes it an insulator), the other diode(s) will do the job. In case of that kind of diode breakage the circuit is like an OR-gate: If diode1 OR diode2 OR ... OR diodeN works properly, then the circuit works properly. If it is important to make sure that the diode does not wrongly conduct, then the diodes should be in series. 2. Reducing the forward voltage: In power electronics high currents need to be conducted with parts that are as ideal as possible (concordantly in this case each diode should be able to carry at least the full current, that has to be transferred through the group of diodes, in order to avoid a cascaded cataclysmic thermal runaway due to a decrease of the forward voltage of the overheated diode).


Does the reverse resistance of a diode stay constant?

A: Actually no. If the current can be limited it may Even oscillate and each diode will behave differently even tough they are from the same family. A reverse breakdown usually means a blown diode in a circuit the hear from a hi voltage and the hi current will surpass its power dissipation and blow short most of the time.


What is cutoff voltage in diodes?

If you're looking for a definition, it's: the voltage at which, a diode can be considered a "short circuit" or low-value resistor It varies with each diode, but most have approximately 0.6 or 0.7 Volts across them when you get almost 1mA flowing FORWARD through them. For light emitting diodes (LEDs), it varies between diodes and is largely dependent on the colour of the light. Green ones typically have 1.3V @ 1mA, red = 1.8V @ 1mA, and higher for other colours. Infrared LEDs usually have 1.1V @ 1mA. Higher cutoff voltages occur at higher forward currents, meaning that at 1mA, Vf might be 1.8V for a certain diode, but at 10mA Vf is maybe 1.9V. One important side note is that reverse current is still possible, but is so small it's usually negligible. Also, it's not recommended to force current backwards through a diode (exception: Zener diodes) because it usually requires a higher voltage to accomplish this. The cutoff voltage of a diode is the maximum voltage that the diode can withstand in the revers biase above which the device will be destroyed.


Do diodes obey Ohms law?

Diodes do not obey Ohm's Law, at least when viewed as an individual component. When doing circuit analysis, however, you can make the case that, for a specific situation, they do. In fact, using this technique, everything "obeys" Ohm's law. In the simple case of a resistor, operated within its limits, Ohm's Law works just fine. Voltage is current times resistance. As voltage goes up, current goes up proportionately. You can predict the voltage or current knowing the other along with resistance. A diode, on the other hand, is non linear. As you apply voltage across it in the forward direction, it initially has high resistance. All of a sudden it has low resistance as it begins to conduct. As you increase the current, the resistance decreases, so the voltage drop is relatively (though not exactly) constant. At a certain point, around when you exceed the maximum forward current, the diode fails. In the reverse direction, an ordinary diode seems to have high resistance, until you reach about max reverse voltage, at which point the diode fails. In the case of a zener diode, reverse behavior is similar to forward behavior, except at a different voltage. Even though the diode does not obey Ohm's law, you can still use Ohm's Law to analyze the circuit. You just have to remember that the dynamic resistance of the diode changes as a function of the applied voltage. The value of Ohm's Law becomes evident when you consider that, at each static condition of the circuit, you do know the voltage and current through the diode and, as a result, you can use Ohm's law to calculate its dynamic resistance. This will allow you to extend the analysis by back substitution and simplification until you know more and more about the circuit.


The total current that flows through a circuit is the same as the current that flows through each individual resistor connected in series?

True

Related questions

What is the difference between diode and resistors?

the resistance of a diode is .4 ohms is made of tantalum or .7 ohms if made of silicon. ANSWER: THE RESISTANCE OF A DIODE IS SIMPLY V/I the impedance however is defines by Boltzmann constant


Why diode use in parallel?

1. Redundancy: If one diode breaks (in a way that makes it an insulator), the other diode(s) will do the job. In case of that kind of diode breakage the circuit is like an OR-gate: If diode1 OR diode2 OR ... OR diodeN works properly, then the circuit works properly. If it is important to make sure that the diode does not wrongly conduct, then the diodes should be in series. 2. Reducing the forward voltage: In power electronics high currents need to be conducted with parts that are as ideal as possible (concordantly in this case each diode should be able to carry at least the full current, that has to be transferred through the group of diodes, in order to avoid a cascaded cataclysmic thermal runaway due to a decrease of the forward voltage of the overheated diode).


A bridge rectifier is supply with 120Vrms sinusoidal signal each diode has a junction voltage of 0.3V determine the peak votage?

v peak = v rms times square root (2) Note: A junction voltage of 0.3V is atypical. Normally a silicon diode has a forward voltage between 0.6 volts to 1.4V depending on current. Are you sure about the forward voltage? Perhaps you are talking about germanium or schottky diodes?


What is the part of a circuit that connects or disconnects the circuit?

Switches, fuses and circuit breakers are examples of some of the electrical parts which can connect or disconnect a circuit to a source of current. A diode does it for alternating current, but only for one half of each cycle. "Connecting" allows an electric current to flow through the circuit. "Disconnecting" stops an electric current from flowing through the circuit.


Why resistance use in silicon diode characteristics?

Resistance is used in characterizing silicon diodes, or any component for that matter, because the equivalent resistance in a certain condition tells you what the circuit will do in that condition. It is true that a diode is not a resistor, but it has an equivalent resistance at each point on it operating curve. Let take three points, for example... With one ampere of current, the forward voltage might be 0.68 volts. That corresponds, using Ohm's law, to a resistance of 0.68 ohms. With ten amperes of current, the forward voltage might be 1.15 volts. That corresponds to a resistance of 0.115 ohms. With 25 amperes of current, the forward voltage might be 1.7 voltage. That corresponds to a resistance of 0.068 ohms. You can obtain the forward resistance curve from the manufacturer's data sheet. Even if there is only a voltage versus current curve, you can calculate resistance using Ohm's law. You need to know the resistance curve in order to design the circuit that uses the diode. In high performance situations, such as in large power supplies, the resistance of the diode may well be critical, and would therefore be a factor in selecting which diode amongst several choices to choose.


How the voltagedrope can be understand in the circuite of and gate using diodes?

A diode while forward conducting follows an exponential curve depending on the current trough. In designing diodes gates it is safe to assume a voltage drop of 0.6volts for each diodes even in a ternary level.


What is PIV in electronics?

The Peak inverse voltage (PIV) equals the peak value of the input voltage, and the diode must be capable of withstanding this amount of repetition reverse voltage. For the diode in figure, the maximum value of reverse voltage, designated as PIV, occurs at peak of each positive alternation of the input voltage when the diode is forward biased.Peak Inverse Voltage at Positive Half CycleThe Peak Inverse Voltage (PIV) occurs at the peak of each half-cycle of the input voltage when the diode is forward biased . In this circuit, the PIV occurs at the peak of each positive half cycle.


Does the reverse resistance of a diode stay constant?

A: Actually no. If the current can be limited it may Even oscillate and each diode will behave differently even tough they are from the same family. A reverse breakdown usually means a blown diode in a circuit the hear from a hi voltage and the hi current will surpass its power dissipation and blow short most of the time.


What is cutoff voltage in diodes?

If you're looking for a definition, it's: the voltage at which, a diode can be considered a "short circuit" or low-value resistor It varies with each diode, but most have approximately 0.6 or 0.7 Volts across them when you get almost 1mA flowing FORWARD through them. For light emitting diodes (LEDs), it varies between diodes and is largely dependent on the colour of the light. Green ones typically have 1.3V @ 1mA, red = 1.8V @ 1mA, and higher for other colours. Infrared LEDs usually have 1.1V @ 1mA. Higher cutoff voltages occur at higher forward currents, meaning that at 1mA, Vf might be 1.8V for a certain diode, but at 10mA Vf is maybe 1.9V. One important side note is that reverse current is still possible, but is so small it's usually negligible. Also, it's not recommended to force current backwards through a diode (exception: Zener diodes) because it usually requires a higher voltage to accomplish this. The cutoff voltage of a diode is the maximum voltage that the diode can withstand in the revers biase above which the device will be destroyed.


How is it possible to test a diode with a multimeter?

The diode must be isolated from any parallel current paths to test. check resistance both directions through diode. readings should show an open (or very high resistance) one direction and a short (or very low resistance) the other direction. Usually, a failed diode will show an open both directions. Set the multimeter to check resistance, attach each meter lead to opposite leads on diode, note reading, then swap meter leads and compare readings.


How do you calculate the voltage across each diode and load resistor in a bridge diode configuration?

Assuming that at one time a positive potential exists on a anode then assign a [+] to that point follow this procedure for all diodes and resistors. You can calculate Boltzmann impedance of a diode but industry wise a .6v to.8v is standard practice for a diode drop since it follow an exponential curve. .6 volts is for low current and .8volts is for more current


What controls the order items are arranged on a slide in Microsoft Powerpoint?

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