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What is the relation between the bandwidth and symbol rate?

the channel capacity (information in bits per second) is related to bandwidth and SNR by the relation C= B[log(1+SNR) b/s log is at the base 2 B= bandwidth of a channel C= capacity in bits per second SNR= signal to noise ratio.


Advantages of large bandwidth?

A very usefull advantage is the exchange of SNR(signal to noise ratio) with Bandwidth... as on increasing the bandwidth the power required for transmission get reduced to a great extent.. is given by the formula SNR2 ~ (SNR1) B1/B2 AS we can see on increasing the bandwidth the SNR is reduced greatly


What is the effect of bandwidth on a digital signals?

Bandwidth is an inherent characteristic of a given transmission channel, or is determined by the narrowest-bandwidth component of the system. The bandwidth of a channel will limit the possible attainable data rates. This is shown simply by Shannon's Theorem, which states C = B log_2 (1+P_signal/P_noise), where C is the channel capacity in bps, B is the channel bandwidth in Hz, P_signal is the power of the detected signal in W, and P_noise is the noise power of the detected signal in W. As an example, consider a standard phone line (i.e., using a dial-up modem). Standard phone lines have a bandwidth of about 3.4 kHz and a signal-to-noise ratio of about 10,000. Using this information, we get C = (3.4 kHz) log_2 (1+10,000) = 45 kbps. Dial-up modems can actually get as high as 56 kbps, but that is beyond the scope of this question. In general Shannon's Theorem can provide a fairly accurate way to predict the possible data rates for a given transmission channel if the bandwidth and resulting signal and noise powers are known.


What is the channel capacity for a teleprinter channel with a 300-hz bandwidth and a signal-to-noise ratio of 3dB?

I m not sure but it should be something like this Shannon capacity(channel capacity) C = B Log2(1+ s/n) C= channel capacity B = bandwidth S/N = signal to noise ratio in power units as the S/n is in db , first we have to convert it. 3db= 10^3/10 = 10^0.3= 1.9926 now putting in the formula C = 300log2(1+ 1.9926) C = 474.81 bps


What are the advantages of instrumentation amplifier over differential amplifier?

a differential amplifier helps to increase the CMRR which in turn helps avoid unwanted signals that couple into the input to get propagated. IT also helps to increase the signal to noise ratio. furthermore it provides larger output voltage swings.

Related Questions

Which factor affect data rate of a link?

the bandwidth and the signal to noise ratio


What is the relation between the bandwidth and symbol rate?

the channel capacity (information in bits per second) is related to bandwidth and SNR by the relation C= B[log(1+SNR) b/s log is at the base 2 B= bandwidth of a channel C= capacity in bits per second SNR= signal to noise ratio.


What is the maximum data rate sustainable by a noisy channel with a bandwidth of 10KHz and a signal to noise ratio of 2047?

110kbps


What is the connection between the bandwidth of a signal and the data rate that it represents?

The data rate (C) is equal to the bandwidth (B) times the logarithm base 2 of 1 plus the signal-to-noise ratio (S/N) (how much interference is introduced in the transmission of data)C = B x log2(1 + S/N)So your data rate is directly proportional to your bandwidth. If you increase your bandwidth, your data rate will also increase provided the signal-to-noise ratio isn't affected.


What do engineers use the signal to noise ratio for?

Signal to noise ratio is a measure of signal strength to the background noise. Engineers use the signal to noise ratio to improve digital signal processing.


What are the three interrelated major elements of cable bandwidth?

Distance, Frequency, and Signal-level-to-noise-level ratio (SNR)


What key features affect the channel capacity?

Key features that affect channel capacity include bandwidth, signal-to-noise ratio, and modulation technique. A wider bandwidth allows for more data to be transmitted, while a high signal-to-noise ratio enables better accuracy in data transmission. The modulation technique used can also impact channel capacity by determining how efficiently the available bandwidth is utilized.


How do you calculate Signal to Noise ratio?

It can be calculated by simplifying the ratio between power of signal by power of noise


What is the signal to noise ratio for the Kenwood KDC-C471FM?

The Kenwood KDC-C471FM has a Signal-to-noise ratio of 100 dB


What is the signal to noise ratio formula in dB?

The signal-to-noise ratio (SNR) formula in decibels (dB) is calculated as 10 times the logarithm base 10 of the ratio of the signal power to the noise power. The formula is: SNR(dB) 10 log10(signal power / noise power).


Advantages of large bandwidth?

A very usefull advantage is the exchange of SNR(signal to noise ratio) with Bandwidth... as on increasing the bandwidth the power required for transmission get reduced to a great extent.. is given by the formula SNR2 ~ (SNR1) B1/B2 AS we can see on increasing the bandwidth the SNR is reduced greatly


Relation between channel capacity and bandwidth?

According to Shannon's Channel Capacity Equation: R = W*log2(1 + C/N) = W*log2(1+ SNR) Where, R = Maximum Data rate (symbol rate) W = Bw = Nyquist Bandwidth = samples/sec = 1/Ts C = Carrier Power N = Total Noise Power SNR = Signal to Noise Ratio