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R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
5 ohms
.9 watts.
According to Ohm's law of resistance in parallel, 1/RT=1/R1+1/R2+1/R3... so 1/RT=1/12+1/4=1/12+3/12=4/12=1/3 and 1/(1/3)=3.The total resistance of the two devices is 3.There is a simpler special case formula for two resistances in parallel:* RTot = (R1R2) / (R1 + R2) In this case this it would give us (12 x 4) / (12 + 4), or 48 / 16 which equals 3 ohms.3 ohms
A simple circuit has three resistors connected in series. The resistors are 14 ohms 12 ohms and 9 ohms. What is the total resistance of the circuit?
In a parallel circuit, the total resistance is calculated as the reciprocal of the sum of the reciprocals of each individual resistance. So, for three resistances of 20 ohms, 20 ohms, and 10 ohms, the total resistance will be 1 / (1/20 + 1/20 + 1/10) = 1 / (0.05 + 0.05 + 0.1) = 1 / 0.2 = 5 ohms.
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).
To calculate resistance in parallel: 1/R = 1/A + 1/B + 1/C + 1/D ... where R is the final result, and A, B, C... are the individual resistances. For two resistances A and B, you can simply calculate (A x B) / (A + B).
R = 1/[1/2 + 1/4 + 1/6 + 1/10] Add up the reciprocals of the resistances, and take the reciprocal of the answer.
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
The equivalent resistance of four resistors in parallel, the resistors being 2, 4, 6, and 8 ohms, is 0.96 ohms. RP = 1 / summationI=1toN (1/RI)
You can consider a short circuit to be a resistor with R=0 Ohms. It is then clear by the equation for calculation of parallel resistance that the combined resistance of a resistor in parallel to a short circuit is 0. Consider the following example with R1= 1k Ohms and R2= 0 Ohms: Rtotal = R1*R2 / (R1+R2) = R1*0 / R1 = 0 Ohms.
For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.For a series circuit such as this, simply add the resistances to get the equivalent resistance.
we have this 1/Re = (1/R1)+(1/R2) for calculating the effective resistance when resistances are connected in parallel so the answer would be Re =( 70*30) / (70+ 30) = 21 ohms
The equivalent resistance is the overall effect all of the resistances in a circuit has. Put another way, it is the value a single resistor in a circuit would have to be in order to have the same effect as all of the resistors resistors combined in a given circuit.
In a series circuit, all components are connected in a single path. An example problem of a series circuit could involve calculating the total resistance when given the individual resistances of each component. For instance, if a circuit has three resistors with values of 10 ohms, 20 ohms, and 30 ohms connected in series, the total resistance can be found by adding the individual resistances together: 10 ohms 20 ohms 30 ohms 60 ohms.