Well, the total circuit resistance depends on the type of connection.
If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms).
If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)Note: If you try this at home, be aware that these resistors will dissipatethe 5 ohm . . . 58.8 wattsthe 10 ohm . . . 117.6 wattsthe 20 ohm . . . 235 watts .These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.
The resistance of a conductor is directly proportional to its length, hence increasing the length twice will increase the resistance twice as well. Therefore the resistance will be 2*10 = 20 Ohms
To find the equivalent resistance of resistors in series, you simply add their resistances together. In this case, the equivalent resistance ( R_{\text{eq}} ) is calculated as follows: [ R_{\text{eq}} = R_1 + R_2 + R_3 = 20 , \text{ohms} + 12 , \text{ohms} + 8 , \text{ohms} = 40 , \text{ohms}. ] Thus, the equivalent resistance of the circuit is 40 ohms.
10 Ohms.
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
In a parallel circuit, the total resistance is calculated as the reciprocal of the sum of the reciprocals of each individual resistance. So, for three resistances of 20 ohms, 20 ohms, and 10 ohms, the total resistance will be 1 / (1/20 + 1/20 + 1/10) = 1 / (0.05 + 0.05 + 0.1) = 1 / 0.2 = 5 ohms.
5 ohms
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
5 ohms
Could it be.... 20 ohms(?)
The question appears to be describing three resistors all in parallel.The reciprocal of their net effective resistance is(1/20) + (1/20) + (1/10) = (2/20) + (1/10) = (1/10) + (1/10) = (2/10) = 1/5.The net effective resistance is [ 1 / (1/5) ] = 5 ohms.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
35 ohms
You must find a resistance value for 0 dB as reference. If 1 Ohm = 0 dB then 10 ohms = 20 dB and 100 ohms = 40 dB.
In a series circuit, all components are connected in a single path. An example problem of a series circuit could involve calculating the total resistance when given the individual resistances of each component. For instance, if a circuit has three resistors with values of 10 ohms, 20 ohms, and 30 ohms connected in series, the total resistance can be found by adding the individual resistances together: 10 ohms 20 ohms 30 ohms 60 ohms.