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At 120 vac what is the amp draw of total resistance series circuit with 5 ohms 10 ohms 20 ohms?
The net effective resistance of 5 ohms, 10 ohms, and 20 ohms in series is 35 ohms.
The current through the net effective resistance is [ I = E/R ] = 120/35 = 3.429 Amp. (rounded)
Note: If you try this at home, be aware that these resistors will dissipate
the 5 ohm . . . 58.8 watts
the 10 ohm . . . 117.6 watts
the 20 ohm . . . 235 watts .
These are no ordinary resistors, such as hang on the wall in plastic bags at Radio Shack.
These would have to be 'power' resistors ... like heating coils in a toaster or hair-dryer.
What else can I help you with?
Is there more resistance in the series circuit or the parallel circuit?
Ohm's Law says! R=V/I Resistance is directly proportional to Voltage. In series circuit, due to adding the resistance, total voltage will be increased, due to increasing of total voltage, total resistance of the series also be increased.
There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
Is the total resistance of all the parallel loads more than the smallest individual resistance?
No. Perhaps an analogy would help understand the answer to this question. When you are at the store, and you are in a line waiting to be paid, opening up another line or more should increase how fast people can move through the store. That is a parallel operation. (If you have to go through one line at the store and then go through another line at the store, that is a series operation). Similarly, when a current meets a resistance, putting additional resistance in PARALLEL allows some of the current to divert to this new path or paths, allowing more current to flow through the combination of resistances. Since more current is flowing though the combined resistances, the equivalent resistance is less since less resistance always means more flow.
What would the current draw be if there was six ten ohm resistors connected in series across a 120 volts?
The total current in a circuit consisting of six operating 100 watt lamps connected in parallel to a 120 volt source is 5 amperes. Since power is volts times amps, take 600 watts (100 times 6) and divide by 120 volts to get 5 amps.
What will be the amps of a 12v 2amp circuit if there is a 12ohm resistor on it?
The formula you are looking for is I = E/R. Amps = Volts/Resistance. If you say it is normally a 2 Amp circuit, it normally draws 2 amps. Therefore the original resistance offered to the 12v battery is 2/12 = 6 Ohms. If you then connect a 12 Ohm resistor in series, they are added, so R = 18 Ohms. Now if you put 12v across this circuit it will draw 12/18 = 0.66 Amps. Or If you just put a 12 Ohm resistor across the 12v supply it will draw 1 Amp. If the circuit is protected by a 2 Amp fuse, it will not blow, but the resistor will get hot.
How is an ammeter connected in a circuit in order to read the current flowing in the circuit?
In series with the circuit and never in parallel. The reason being that it will cause the circuit total resistance to drop which will make the circuit draw excessive current. That's a short circuit actually.
How to determine amp draw in an electrical circuit?
To determine amp draw in an electrical circuit, you can use Ohm's Law, which states that current (amps) equals voltage divided by resistance. Measure the voltage across the circuit and the resistance of the components in the circuit, then divide the voltage by the resistance to calculate the amp draw.
Is there more resistance in the series circuit or the parallel circuit?
Ohm's Law says! R=V/I Resistance is directly proportional to Voltage. In series circuit, due to adding the resistance, total voltage will be increased, due to increasing of total voltage, total resistance of the series also be increased.
Why are the equations for working out the current in a parrel circuit inverse?
In a parallel circuit the voltages for each component are all the same, and the current is shared, each component drawing a current depending on its conductance. In a series circuit, the current in each component is the same, and so each one gets a voltage proportional to its resistance.
In parallel circuit whathappens to the total resistance if one branch opens-Provide an example?
In a parallel circuit, each load added subtracts from total resistance. When one or more loads is removed from a parallel circuit, the total resistance is increased, reducing the total amperage draw. The less resistance a load has, the more current can pass through. This is part of Ohm's law. The mathematical equation that describes Ohm's law is: I=V/R , where I is the current in amperes, V is the potential difference in volts,and R is a circuit parameter called the resistance For example : The humble light-bulb is rated by the watts it uses. The amount of watts used by a light-bulb is calculated using Ohm's law. With the resistance of the bulb's filament and the voltage the bulb is designed to operate with, one can derive the amperage the bulb will draw. The amperage is then multiplied by the voltage to show wattage. Using Ohm's law : With the resistance of a 40watt 120volt light-bulb, only 0.33amps is able to pass through the bulb's 363ohm filament at 120volts. A lamp that has two 40watt bulbs inplace, and the two bulbs are in parallel, the circuit will have a resistance of 179ohms and draw 0.67amps which is 80watts at 120volts.
Why fuse wire is placed in series with the device?
circuit breaker and fuses used in series to break the circuit in overcurrent situation to block current to flow through circuit.
What will happen if a voltmeter has a low shunt resistance instead of having high shunt resistance?
The purpose of a voltmeter is to indicate the potential difference between two points in a circuit.When a voltmeter is connected across a circuit, it shunts the circuit. If the voltmeter has a low resistance,it will draw a substantial amount of current. This action lowers the effective resistance of the circuit andchanges the voltage reading.
What is the current draw for a ford fuel pump?
approximately 5.7 to 6.0 amps depending on temperature , load, and circuit resistance.
Why does parallel circuit have higher current than the series?
Parallel branches each draw a current from the supply. The more branches, the more current is drawn. Adding additional loads to a series circuit increases its resistance, causing its supply current to reduce.
How do you calculate thevenis resistance in thevenis ckt?
First,remove all current and voltage sources ie replace voltage source with a short and keep current source open.Now draw the equivalent resistance-only circuit and find the equivalent resistance as viewed from the terminals of the circuit.
Does a volt meter takes power from the system?
No it does not. A volt meter only reads the current that is passing through it.AnswerAll instruments draw some (albeit tiny) current from the circuit under test in order to operate. So, if this is what you mean by 'taking power from circuit', then the answer is yes, it does.Instruments also change the normal resistance of the circuit being tested -for example, ammeters increase the resistance of the circuit into which they are connected, while voltmeters decrease the circuit resistance across which they are connected. So adding a voltmeter (or an ammeter) to a circuit affects the operation of that circuit to some degree. To minimise this interference, it is important that an ammeter's internal resistance is very much lower than the circuit's resistance, and a voltmeter's resistance is very much higher than the circuit's resistance.
There are three sources of resistance in a parallel circuit Two of them are rated at 20 ohms the other at 10 ohms What is the circuit's total resistance?
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
