Could it be.... 20 ohms(?)
35 ohms
Three resistors in parallel: 20 ohms, 20 ohms, 10 ohms.1/ total resistance = (1/10) + (1/20) + (1/20) = (2/20) + (1/20) + (1/20) = 4/20 = 1/5 mho.Total resistance = 5 ohms
In a parallel circuit, the total resistance is calculated as the reciprocal of the sum of the reciprocals of each individual resistance. So, for three resistances of 20 ohms, 20 ohms, and 10 ohms, the total resistance will be 1 / (1/20 + 1/20 + 1/10) = 1 / (0.05 + 0.05 + 0.1) = 1 / 0.2 = 5 ohms.
5 ohms
5 ohms
When a resistor is in series. Total resistance =R1+T2+R3. Therefore 20+8+4=32 The total resistance is 32 ohms.
The total resistance is 5 ohms. Scroll down to related links and look at "Parallel Resistance Calculator".
5 ohms
For an end-result of 10 ohms, you can have 1 resistance of 10 ohms, or 2 parallel resistance of 20 ohms each, or 3 resistances of 30 ohms each, etc.
If they're connected in series the total resistance is 2000 ohms. If they're connected in parallel the resistance is 500 ohms.
Well, honey, in a parallel circuit, you can't just add up the resistances like you're at a buffet. You gotta use the formula 1/Rtotal = 1/R1 + 1/R2 + 1/R3. Plug in the values and you'll find the total resistance is 6.67 ohms. So, grab your calculator and get to work, darling.
Well, the total circuit resistance depends on the type of connection. If the two resistances (or any number of resistances) are connected in series, IE. one resistance end is connected to one end of another resistance, the the circuit total resistance is the sum of the two resistances. say two resistances r1 and r2 are connected in series the total resistance is r1+r2 (in this case its 30 ohms). If the resistances are connected in parallel IE. both the ends of a resistance are connected to both ends of another resistance then the total resistance in this case shall be (r1*r2)/(r1+r2) ,( that is 6.67 ohms in given case).